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3 years ago

Do the ratios 11/15 and 1/6 form a proportion?

Mathematics

1 answer:

IceJOKER [234]3 years ago

4 0

Answer: No, the ratios 11/15 and 1/6 do not form a proportion.

Explanation: Proportion says that two ratios (or fractions) are equal.

Example:

Proportion 1/3 : 2/6

So 1-out-of-3 is equal to 2-out-of-6

The ratios are the same, so they are in proportion.

If I multiplied 1 by 11 and then 6 by 11, I would get 11/66, therefore 11/15 and 1/6 do not form a proportion.

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In the figure below, \overline{AD} AD start overline, A, D, end overline and \overline{BE} BE start overline, B, E, end overline

VLD [36.1K]

Answer:

<u>The measure of the arc CD = 64°</u>

Step-by-step explanation:

It is required to find the measure of the arc CD in degrees.

So, as shown at the graph

BE and AD are are diameters of circle P

And ∠APE is a right angle ⇒ ∠APE = 90°

So, BE⊥AD

And so, ∠BPE = 90° ⇒(1)

But it is given: ∠BPE = (33k-9)° ⇒(2)

From (1) and (2)

∴ 33k - 9 = 90

∴ 33k = 90 + 9 = 99

∴ k = 99/33 = 3

The measure of the arc CD = ∠CPD = 20k + 4

By substitution with k

<u>∴ The measure of the arc CD = 20*3 + 4 = 60 + 4 = 64°</u>

6 0

3 years ago

A package contains 12 resistors, 3 of which are defective. If 4 are selected, find the probability of getting

s344n2d4d5 [400]

Answer:

Incomplete question, but I gave a primer on the hypergeometric distribution, which is used to solve this question, so just the formula has to be applied to find the desired probabilities.

Step-by-step explanation:

The resistors are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

12 resistors, which means that $N = 12$

3 defective, which means that $k = 3$

4 are selected, which means that $n = 4$

To find an specific probability, that is, of x defectives:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = x) = h(x,12,4,3) = \frac{C_{3,x}*C_{9,4-x}}{C_{12,4}}$

7 0

3 years ago

PLEASE can anyone help me with this problem??

Lilit [14]

9514 1404 393

Answer:

Step-by-step explanation:

To find the value of g(7), locate 7 on the x-axis. Follow the grid line upward until it meets the graph (blue line). At that point, follow the grid line to the left until it meets the y-axis. Read the value from the scale on the y-axis.

g(7) = 4

5 0

4 years ago

Find the distance between (-4,0) and (8,-3)

Dennis_Churaev [7]

Answer:

12.3693

Step-by-step explanation:

use distance formula

3 0

3 years ago

Find the coordinates of the midpoint of the segment whose endpoints are (-4, 6) and (-8, -2).

belka [17]

The midpoint is (-6,2)

8 0

3 years ago

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