Answer:
m=2
Step-by-step explanation:
When you put a number into the inverse of a function (f^-1) you get the original number back.
Ex: f^-1(11) = (11-3)/2 = 4
f(4) = 2×4+3 = 11
So, f(-5)=-2
So, when x is -5,
f(x) = -2
f(x)=m(-5)+8
-2=m(-5) + 8
m=2
Answer:
m∠x = 10°
Step-by-step explanation:
Since we are dealing with a <u>right triangle</u> and its two sides and one angle, we can use <u>trigonometry ratios</u>. Remember them all with the acronym SohCahToa.
"o" is for opposite side, "a" is for adjacent side, "h" is for hypotenuse side.
The ratios are:
sinθ = opposite/hypotenuse
cosθ = adjacent/hypotenuse
tanθ = opposite/adjacent
θ means the "angle of reference", or the angle you know or want to find. This determines which side is adjacent (touching) or opposite (not touching). The hypotenuse (longest side) does not change.
In this triangle, θ = x. The sides we know are hypotenuse and opposite. Therefore, we will use the sinθ ratio.
sinθ = opposite/hypotenuse
sinx = CB/AB Substitute the labels in the diagram
sinx = 4/23 Substitute known values (side lengths)
x = sin⁻¹(4/23) Isolate 'x'. Use calculator to solve.
x = 10.015....° Exact answer
x ≈ 10° Round to the nearest degree
Therefore the measure of angle x (m∠x) is 10°.
bearing in mind that standard form for a linear equation means
• all coefficients must be integers, no fractions
• only the constant on the right-hand-side
• all variables on the left-hand-side, sorted
• "x" must not have a negative coefficient
![\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1)}=\stackrel{m}{\cfrac{8}{9}}[x-\stackrel{x_1}{(-4)}]\implies y+1=\cfrac{8}{9}(x+4) \\\\\\ \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{9}}{9(y+1)=9\left( \cfrac{8}{9}(x+4) \right)}\implies 9y+9=8(x+4)\implies 9y+9=8x+32 \\\\\\ 9y=8x+23\implies -8x+9y=23\implies 8x-9y=-23](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Bpoint-slope%20form%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y-y_1%3Dm%28x-x_1%29%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%5Cimplies%20y-%5Cstackrel%7By_1%7D%7B%28-1%29%7D%3D%5Cstackrel%7Bm%7D%7B%5Ccfrac%7B8%7D%7B9%7D%7D%5Bx-%5Cstackrel%7Bx_1%7D%7B%28-4%29%7D%5D%5Cimplies%20y%2B1%3D%5Ccfrac%7B8%7D%7B9%7D%28x%2B4%29%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bmultiplying%20both%20sides%20by%20%7D%5Cstackrel%7BLCD%7D%7B9%7D%7D%7B9%28y%2B1%29%3D9%5Cleft%28%20%5Ccfrac%7B8%7D%7B9%7D%28x%2B4%29%20%5Cright%29%7D%5Cimplies%209y%2B9%3D8%28x%2B4%29%5Cimplies%209y%2B9%3D8x%2B32%20%5C%5C%5C%5C%5C%5C%209y%3D8x%2B23%5Cimplies%20-8x%2B9y%3D23%5Cimplies%208x-9y%3D-23)
True. 8*9=72 and 9*9=81. Original ratio is being multiplied by 9/9
Answer: Darla would have to pay $17.69 before tax
Step-by-step explanation:
Total amount in Darla's wallet = $15
She intends buying 2 gallons of fruit, 3 bags of chips and a box of cupcakes.
For the gallon of fruit
The first gallon of fruit cost $3.50
The second gallon of fruit has a discount of 50%. We have
(50/100) * 3.50
= $1.75
Therefore, the total amount for the two gallons of fruit =$3.50 + $1.75
= $5.25
Bag of chips
2 bags of chips cost $5 while 1 bag of chips cost $2.65
Since she intends to buy 3 bags of chips we have $5 + $2.65 = $7.65
1 box of cupcakes = $4.79
The total amount Darla is to pay for the groceries before tax equals
$5.25 + $7.65 + $4.79
= $17.69
This is more than the amount Darla has in her wallet
