Answer:
Population mean = 7 ± 2.306 × 
Step-by-step explanation:
Given - A university researcher wants to estimate the mean number
of novels that seniors read during their time in college. An exit
survey was conducted with a random sample of 9 seniors. The
sample mean was 7 novels with standard deviation 2.29 novels.
To find - Assuming that all conditions for conducting inference have
been met, which of the following is a 94.645% confidence
interval for the population mean number of novels read by
all seniors?
Proof -
Given that,
Mean ,x⁻ = 7
Standard deviation, s = 2.29
Size, n = 9
Now,
Degrees of freedom = df
= n - 1
= 9 - 1
= 8
⇒Degrees of freedom = 8
Now,
At 94.645% confidence level
α = 1 - 94.645%
=1 - 0.94645
=0.05355 ≈ 0.05
⇒α = 0.5
Now,
= 0.025
Then,
= 2.306
∴ we get
Population mean = x⁻ ± ×
= 7 ± 2.306 ×
⇒Population mean = 7 ± 2.306 ×
Answer:she has 20 pennies because
Step-by-step explanation:80 divide by 4 = 20
Answer:
510/600 of the shirts are not yellow or pink.
Step-by-step explanation:
First we turn 7/200 with a denominator of 600.
7/200 = 21/600
Next we add 69/600 with 21/600.
69/600 + 21/600 = 90/600
Now we subtract 600 by 90.
600 - 90 = 510.
So, the answer is 510/600
Hope this helps! :)
A. 2067.
6890 time .30 (30 percent) is 2067
B. 4823
inital ammount minus down payment
6890 - 2067 = 4823
C 134.08
Total ammount multiplied by percentage (0.0278)
4823 * .0278 = 134.079 per month
D.1612.81
find total paid and subtract initial ammount to find finance charge
(134.08*48)= 6435.81
6435.81-4824 = 1612.81
Answer:
I believe it would be equality.
Step-by-step explanation:
Equality means "The state of being equal". All of those problems equal 12 and not separate numbers, if they equaled different numbers then it would be congruence, therefor your answer is equality.
Hope this helps :)
