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2 years ago

If m<13=73, find m<20

Mathematics

1 answer:

kodGreya [7K]2 years ago

8 0

Answer:

m<20 = 107 degrees

Step-by-step explanation:

m<20 = 180-73 parts whole

m<20 = 107 degrees

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Cory made 4,500 g of candy. He saved 1 kg to eat later. He divided the rest of the candy over 7 bowls to

Olenka [21]

Answer: 500 g of candy in each bowl

Step-by-step explanation:

1,000 g = 1Kg

4,500 g - 1,000 g = 3,500 g of candy were divided over 7 bowls:

Each bowl contains = 3,500 g➗7 bowls = 500 g candy/bowl

Answer: 500 g of candy in each bowl

<h2><em>Spymore</em></h2>

4 0

3 years ago

devi bought 7 skirts at x$ each n skirts at 12$ each 2n +1 at 15 each a nd 4 skirts at $3x find the total

nikitadnepr [17]

Answer:

$(19x + 42n + 15)

Step-by-step explanation:

Devi bought 7 skirts at $x each, n skirts at $12 each, (2n + 1) skirts at $15 each and 4 skirts at $3x each. Find the total cost of the skirts she bought.

total cost of the skirt bought can be determined by adding the total costs of each shirt bought

7 skirts at $x each = $7x

n skirts at $12 each = $12n

(2n + 1) skirts at $15 = (2n + 1) x 15 = 30n + 15

4 skirts at $3x each = $12x

7x + 12n + 30n + 15 + 12x

combine like terms

19x + 42n + 15

7 0

3 years ago

Find an equation equivalent to r = 10 sinθ in rectangular coordinates

Flura [38]

Answer:

$x^{2} + y^{2} - 10\cdot y = 0$

Step-by-step explanation:

The following expressions are used to transform from polar into rectangular form:

$r = \sqrt{x^{2}+y^{2}}$

$\sin \theta = \frac{y}{\sqrt{x^{2}+y^{2}}}$

Now, the variables are substituted and equation is finally simplified:

$\sqrt{x^{2}+y^{2}} = 10\cdot \frac{y}{\sqrt{x^{2}+y^{2}} }$

$x^{2}+y^{2} = 10\cdot y$

The equivalent equation in rectangular coordinates is:

$x^{2} + y^{2} - 10\cdot y = 0$

8 0

3 years ago

(3.8 x 10 ^ -6) x (2.37 x 10 ^ -3)<br><br> Enter the answer in science notification

Black_prince [1.1K]

Multiply the coefficients and the powers of 10 with each other:

$(3.8 \times 10^{-6}) \times (2.37 \times 10^{-3}) = (3.8\times2.37) \times (10^{-6} \times10^{-3})$

The numeric part simply yields

$3.8\times2.37 = 9.006$

As for the powers of 10, you have to add the exponents, using the rule

$a^b \times a^c = a^{b+c}$

So, we have

$10^{-6} \times10^{-3} = 10^{-6-3} = 10^{-9}$

So, the final answer is

$9.006\times 10^{-9}$

7 0

3 years ago

Please I really need help

Zepler [3.9K]

Answer:

$\bold{q(x)=\{5x-12\}+\{-6x-12\}}$

Step-by-step explanation:

Where it says $q(x)=a(x)+b(x)$ , it simply means: the answer to $q(x)$ is adding both functions, $5x-12$ ( $a(x)$ ) and $-8\times2-6x+4$ ( $b(x)$ ).

First, let us solve $a(x)$

$5x-12$

As we can see, this equation cannot be further simplified. So, this is our final result for this problem.

Next, let us solve $b(x)$

$-8\times2-6x+4$

Multiply -8 and 2

-8 × 2 = -16

[remember your integer rules: a negative times a negative is a positive.]

So we have:

$-16-6x+4$

Combine like terms: -16 and 4 are terms that are alike based on them being integers, but -6x id not because it contains a variable. When you combine you are adding.

-16 + 4 = -12

Now we have:

$-6x-12$

As we can see, this equation cannot be further simplified. So, this is our final result for this problem.

Lastly, combine these results.

$q(x)=\{5x-12\}+\{-6x-12\}$

Therefore, that is the answer.

6 0

3 years ago