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3 years ago

In AWXY, WY is extended through point Y to point Z, m_YW X = (2x + 12),

Mathematics

1 answer:

Alja [10]3 years ago

4 0

Answer:

Sum of two interior angles=exterior angle

$\\ \sf\longmapsto 2x+12+2x+5=7x-1$

$\\ \sf\longmapsto 4x+17=7x-1$

$\\ \sf\longmapsto 3x=18$

$\\ \sf\longmapsto x=6$

Done!

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If a farmer sells 9.8 KL of apples and pears at the farmers market. 4/5 of this weight is apples,and the rest are pears. How man

faltersainse [42]

Answer:

1.96

Step-by-step explanation:

A farmer sells 9.8 kl of apples and pears

4/5 of this weight is apples, while the rest are pears

Therefore the wight of pears can be calculated as follows

Let x represent the weight of pears

9.8= 4/5×9.8 + x

9.8= 0.8×9.8+x

9.8= 7.84+x

9.8-7.84= x

x= 1.96

8 0

3 years ago

Suppose that, after measuring the duration of many telephone calls, a telephone company found their data was well-approximated b

Musya8 [376]

Answer:

a) 7.79%

b) 67.03%

c) Cumulative Distribution Function

$P(t) = \displaystyle\int^{\infty}_{-\infty} 0.1e^{-0.1t}~dt\\\\= \displaystyle\int^{b}_{a} 0.1e^{-0.1t}~dt, ~~a\leq t \leq b$

Step-by-step explanation:

We are given the following in the question:

$p(x) = 0.1 e^{-0.1x}$

where x is the duration of a call, in minutes.

a) P( calls last between 2 and 3 minutes)

$=\displaystyle\int^3_2 p(x)~ dx\\\\= \displaystyle\int^3_20.1e^{-0.1x}~dx\\\\=\Big[-e^{-0.1x}\Big]^3_2\\\\=-\Big[e^{-0.3}-e^{-0.2}\Big]\\\\= 0.0779\\=7.79\%$

b) P(calls last 4 minutes or more)

$=\displaystyle\int^{\infty}_4 p(x)~ dx\\\\= \displaystyle\int^{\infty}_40.1e^{-0.1x}~dx\\\\=\Big[-e^{-0.1x}\Big]^{\infty}_4\\\\=-\Big[e^{\infty}-e^{-0.4}\Big]\\\\=-(0- 0.6703)\\= 0.6703\\=67.03\%$

c) cumulative distribution function

$P(t) = \displaystyle\int^{\infty}_{-\infty} 0.1e^{-0.1t}~dt\\\\= \displaystyle\int^{b}_{a} 0.1e^{-0.1t}~dt, ~~a\leq t \leq b$

6 0

3 years ago

Who likes anime??<br> I like anime‍♀️......

MA_775_DIABLO [31]

Answer:

Me too

Step-by-step explanation:

4 0

3 years ago

Helppp<br> True or false: f(x) represents a function.

Nadusha1986 [10]

I think false because there can’t be a lot of “y” for one “x”

7 0

3 years ago

Rhett is solving the quadratic equation 0= x2 – 2x – 3 using the quadratic formula. Which shows the correct substitution of the

Artemon [7]

Answer:

StartFraction 2 plus or minus StartRoot (negative 2) squared minus 4(1)(negative 3) EndRoot Over 2(1) EndFraction

Step-by-step explanation:

General quadratic equation: ax^2 + bx + c

where a is the coefficient of the quadratic term, b is the coefficient of the linear term and c is the independent term. Here the equation is: x^2 – 2x – 3, so a = 1, b = -2 and c = -3

Quadratic formula:

$x = \frac{-b \pm \sqrt{b^2-4(a)(c)}}{2(a)}$

Replacing

$x = \frac{2 \pm \sqrt{(-2)^2-4(1)(-3)}}{2(1)}$

8 0

3 years ago

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