You have to show your equation, pls!
Let X be the width of the path.
The width of the path would be the width of the pool plus 2x, so 2x +16
The length of the path would be the length of the pool plus 2x, so 2x+22
The total area is 832 square feet.
Area is found by multiplying the length by the width.
So you have:
(2x+16) (2x+22) = 832
Use the Foil Method:
(2x+16) (2x+22) = 4x^2 +76x+352
Now you have:
4x^2 +76x+352 = 832
Subtract 832 from both sides:
4x^2 +76x+352-832 = 0
Simplify:
4x^2 +76x -480
Factor the left side:
4(x-5)(x+24) = 0
Divide both sides by 4:
(x-5)(x+24) = 0
Set both parenthesis to equal 0 and solve for x:
x=5 and x = -24
The width of the path cannot be a negative number, so the width is 5 meters.
Solve for y in the first equation
-y=-x+10
y=x-10
Now substitute y in the second equation
x^2-(x-10)^2=40
x^2-(x^2-20x+100)=40
20x-100=40
20x=140
x=7
Plug the value of 7 in to any of the equations
7-y=10
y=(-3)
Final answer: y= -3
Answer:
For some sets of data, some of the largest value, smallest value
, first quartile, median, and third quartile may be the same. For instance, you might have a data set in which the median and the third quartile are the same. In this case, the diagram would not have a dotted line inside the box displaying the median. The right side of the box would display both the third quartile and the median. For example, if the smallest value and the first quartile were both one, the median and the third quartile were both five, and the largest value was seven, the box plot would look like:
In this case, at least
25
25
% of the values are equal to one. Twenty-five percent of the values are between one and five, inclusive. At least
25
25
% of the values are equal to five. The top
25
25
% of the values fall between five and seven, inclusive.