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Mice21 [21]
3 years ago
11

How many ways can a 4 digit password be formed?

Mathematics
2 answers:
Stella [2.4K]3 years ago
8 0
We have 10 digits to choose 4 digits.
If repetition is allowed, we'd have 10 digits in the first slot, 10 digits in the second slot, and so on.
Hence, there are 10 000 ways to pick 4 digits.

Now, if repetition is not allowed, then we need to change the restrictions somehow.
If numbers cannot be repeated, then we can have 10 in the first slot, 9 in the second slot, 8 in the third slot, and 7 in the fourth slot, which makes 5040 ways.

If we want to understand this in permutations, then we have 10 objects to pick 4 different numbers, and so we can have 10P4 ways in forming a 4-digit password.
Alex_Xolod [135]3 years ago
3 0
<span> it can be solved in over 9000 ways possibility  </span>
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A sequence starts 1,5,9,13,17<br> What’s the formula for the nth term of this sequence??
worty [1.4K]

This is an arithmetic sequence, since it's pattern is +4.

n1 = 1

d = 4

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4 years ago
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What are the zeros of f(x) = x2 + x - 20?
jeyben [28]

Answer:

x = - 5, x = 4

Step-by-step explanation:

Given

f(x) = x² + x - 20

To find the zeros equate f(x) to zero, that is

x² + x - 20 = 0

Consider the factors of the constant term ( - 20) which sum to give the coefficient of the x- term ( + 1)

The factors are + 5 and - 4, since

5 × - 4 = - 20 and + 5 - 4 = + 1, hence

(x + 5)x - 4) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 5 = 0 ⇒ x = - 5

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8 0
3 years ago
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A cone and a triangular pyramid have a height of 9.3 m
Otrada [13]

Answer:

x=17.1\ in

Step-by-step explanation:

<u><em>The complete question is</em></u>

A cone and a triangular pyramid have a height of 9.3 m  and their cross-sectional areas are equal at every level  parallel to their respective bases. The radius of the base of the cone is 3 in and the other leg (not x) of the triangle base of the triangular pyramid is 3.3 in

What is the height, x, of the triangle base of the  pyramid? Round to the nearest tenth

The picture of the question in the attached figure

we know that

If their cross-sectional areas are equal at every level  parallel to their respective bases and the height is the same, then their volumes are equal

Equate the volume of the cone and the volume of the triangular pyramid

\frac{1}{3}\pi r^{2}H=\frac{1}{3}[\frac{1}{2}(b)(h)H]

simplify

\pi r^{2}=\frac{1}{2}(b)(h)

we have

r=3\ in\\b=3.3\ in\\h=x\ in\\pi=3.14

substitute the given values

(3.14)(3)^{2}=\frac{1}{2}(3.3)(x)

solve for x

28.26=\frac{1}{2}(3.3)(x)

x=28.26(2)/3.3\\x=17.1\ in

7 0
3 years ago
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The perimeter of the isoceles triangle is 54. The ratio of the leg to the base is 7:4. Find the length of the base
Norma-Jean [14]

9514 1404 393

Answer:

  12 units

Step-by-step explanation:

The ratio of the base to the other sides is ...

  4 : 7 : 7

The perimeter is a total of 4 +7 +7 = 18 ratio units, so each ratio units stands for 54/18 = 3 length units.

The base length is then ...

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4 0
3 years ago
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