Answer:
For the first question, the answer is 4/3. For the second it is 16.
Step-by-step explanation:
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2.7/6=x/18
2.7 x 18 = 6x
48.6 = 6x
8.1= x
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If the radio active isotope has the half life of 24100 years, then the initial quantity is 2.16 grams
The half life in years = 24100
Consider the quantity of the radio active isotope remaining
y = 
When t = 1000 the y = 1.2
y = C/2 when t = 1599
Substitute the values in the equation
C/2 = 
Cancel the C in both side
1/2 = 
Here we have to apply ln to eliminate the e terms
ln (1/2) = 24100k
k = ln(1/2) / 24100
k = -2.87× 10^-5
To find the initial value we have to substitute the value of k and y in the equation
1.2 = Ce^{1000 × -2.87× 10^-5}
C = 1.2 / e^(-0.0287)
C = 2.16 gram
Hence, the initial quantity of the radioactive isotope is 2.16 gram
Learn more about half life here
brainly.com/question/4318844
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Answer:
x=10
Step-by-step explanation:
Use pythagorean theorem because the triangle is right-angled triangle.
6²+8²=x²
36+64=x²
100=x²
x=√100
x=10
No because 3 can go into 63 evenly and the denominator would be left the same.