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chubhunter [2.5K]
3 years ago
14

6 labour complete a work in 12 days. How many labours should added to complete the works in 8 days?​

Mathematics
1 answer:
mario62 [17]3 years ago
7 0

Answer:

9 labours

Step-by-step explanation:

In order to solve this, we must know which kind of proportionality is this. There are two types of proportions, direct and indirect/inverse proportions. In direct proportion, if one quantity increases, the other quantity also increases.

In indirect proportion, if one quantity increases, the other decreases and vice versa.

As per this question, we know if the number of labour increases, the number of days to complete a work decreases, thus proving that this is an indirect/inverse proportion.

6 labours => 12 days

x labours =>  8 days

Since its an inverse proprotion, multiply 6 with 12, and x with 8.

8x = 6 × 12

x = \frac{6*12}{8}

∴ x = <u>9 labours</u>

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Are associative properties true for all integers
faust18 [17]
The answer is "yes" for all integers.

This property is mainly used to either simplify the expressions or to group alike terms together. It is applicable only for operations of addition and multiplication.

Examples:
57x + 94 xy = x (57+94y)
2ab - 6abc = 2ab (1-3c)


6 0
3 years ago
Suppose that $a$ is a positive integer for which the least common multiple of $a+1$ and $a-5$ is $10508$. What is $a^2 - 4a + 1$
Nana76 [90]

Answer:

21022.

Step-by-step explanation:

Find the prime factors of 10508:

2 ) 10508

2 ) 5254

37 ) 2627

       71.

50208 = 2*2*37*71.

Now there is no integer value for a that would fit  (a+ 1)(a - 5) = 10508 .

But we could try multiplying the LCM by 2:-

= 21016  = 2*2*2*37*71.

= 2*2*37 multiplied by 2 * 71

= 148 * 142.

That looks promising!!

a - 5 = 142 and

a + 1 = 148

This gives  2a - 4 = 290

2a = 294

a = 147.

So substituting a = 147 into a^2 - 4a + 1 we get:

= 21022.

4 0
4 years ago
A lab animal may eat any one of three foods each day. Laboratory records show that if the animal chooses one food on one trial,
Tresset [83]

Answer:

The probability that it will choose food #2 on the second trial after the initial trial = 0.3125

Step-by-step explanation:

Given - A lab animal may eat any one of three foods each day. Laboratory records show that if the animal chooses one food on one trial, it will choose the same food on the next trial with a probability of 50%, and it will choose the other foods on the next trial with equal probabilities of 25%.

To find - If the animal chooses food #1 on an initial trial, what is the probability that it will choose food #2 on the second trial after the initial trial?

Proof -

By the given information, we get the stohastic matrix

H = \left[\begin{array}{ccc}0.5&0.25&0.25\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]

As we know that,

The matrix is a Markov chain x_{k+1} = Hx_{k}

Let

The initial state vector be

x_{0} = \left[\begin{array}{ccc}1\\0\\0\end{array}\right]

we choose this initial vector because given that If the animal chooses food #1 on an initial trial.

Now,

x_{1} = Hx_{0} \\ = \left[\begin{array}{ccc}0.5&0.25&0.25\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]\left[\begin{array}{ccc}1\\0\\0\end{array}\right] \\= \left[\begin{array}{ccc}0.5\\0.25\\0.25\end{array}\right]

∴ we get

x_{1} = \left[\begin{array}{ccc}0.5\\0.25\\0.25\end{array}\right]

Now,

x_{2} = Hx_{1} \\ = \left[\begin{array}{ccc}0.5&0.25&0.25\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]\left[\begin{array}{ccc}0.5\\0.25\\0.25\end{array}\right] \\= \left[\begin{array}{ccc}0.25+0.0625+0.0625\\0.125+0.125+0.0625\\0.125+0.0625+0.125\end{array}\right]\\= \left[\begin{array}{ccc}0.375\\0.3125\\0.3125\end{array}\right]

∴ we get

x_{2} = \left[\begin{array}{ccc}0.375\\0.3125\\0.3125\end{array}\right]

∴ we get

The probability that it will choose food #2 on the second trial after the initial trial = 0.3125

4 0
3 years ago
In a class, two out of every 10 students fails. If there are 50 students in the class, how many pass the test​
Alexandra [31]

Step-by-step explanation:

thank \: you

8 0
3 years ago
Read 2 more answers
The value of new cars at a local dealership is normally distributed with a mean of $34,600 and a standard deviation of $3,000. W
Vinvika [58]

Answer:

The percentage that a new car is expected to have a sticker price of between $31,600 and $40,600 is 81.86%.

Step-by-step explanation:

The random variable <em>X</em> is defined as the value of new cars at a local dealership.

The mean of the random variable <em>X</em> is, <em>μ</em> = $34,600 and the standard deviation is, <em>σ</em> = $3,000.

The random variable <em>X</em> is normally distributed.

Compute the probability that a new car is expected to have a sticker price of between $31,600 and $40,600 as follows:

P(31600

The percentage is, 0.8186 × 100 = 81.86%.

Thus, the percentage that a new car is expected to have a sticker price of between $31,600 and $40,600 is 81.86%.

7 0
3 years ago
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