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2 years ago

How many 2/3s are in 1

Mathematics

1 answer:

Lisa [10]2 years ago

6 0

Answer:

Step-by-step explanation:

you cant fit more than one 2/3's in 1

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Can someone plz answer this not in decimals <br> 17 divided by 1,569

nordsb [41]

Answer:

in fraction from it is $\frac{17}{1569}$

Step-by-step explanation:

7 0

2 years ago

Please read and answer the problem and show your work

PilotLPTM [1.2K]

Answer:

x > -4.

Step-by-step explanation:

Solving for x by dividing -3 to both side leaving x by itself.

When dividing or multiplying a negative value that has a variable the inequality switches sides. Instead of x < -4 it is x > -4. For more information or to understand inequality search for inequality video online.

7 0

1 year ago

∠3 and ∠6 can be classified as:

anastassius [24]

Answer:

Alternate Interior Angles

Step-by-step explanation:

Since they are inside the parallel lines, Alternate Exterior Angles and any other similar theorems can be ruled out.

Since they are on opposite sides of each other, Corresponding Angles and any other similar theorems can be ruled out.

Since they are far apart from each other, Supplementary Angles, Adjacent Angles, Vertical Angles, and any other similar definitions can be ruled out.

Therefore, we are left with Alternate Interior Angles.

6 0

3 years ago

Read 2 more answers

What is the equation of the quadratic graph with a focus of (3, 1) and a directrix of y = 5?

telo118 [61]

Answer:

$f(x)=-\frac{1}{8}(x-3)^2+3$

Step-by-step explanation:

We want to find the equation of the parabola with a focus of $(3,1)$ and directrix $y=5$ .

Considering the directrix, the quadratic graph must open downwards.

The equation of this parabola is given by the formula,

$(x-h)^2=4p(y-k)$ , where $(h,k)$ is the vertex of the parabola.

The axis of this parabola meets the directrix at $(3,5)$ .

Since the vertex is the midpoint of the focus and the point of intersection of the axis of the parabola and the directrix,

$h=\frac{3+3}{2}=3$ and $k=\frac{5+1}{2}=3$ .

The equation of the parabola now becomes,

$(x-3)^2=4p(y-3)$ .

Also $|p|$ is the distance between the vertex and the directrix.

$|p|=2$

This implies that $p=-2\:or\:2$ .

Since the parabola turns downwards,

$p=-2$ .

Our equation now becomes,

$(x-3)^2=4(-2)(y-3)$ .

$(x-3)^2=-8(y-3)$ .

We make y the subject to get,

$y=-\frac{1}{8}(x-3)^2+3)$ .

This is the same as

$f(x)=-\frac{1}{8}(x-3)^2+3)$ .

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2 years ago

I will mark you brainiest if you can answer this

yanalaym [24]

22 touchdowns and 13 field goals

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2 years ago