One stratagie you can use is called the big 7
6 hours Zoey can expect from the tablet on a full battery charge if the battery dropped by 33%, from 100% to 67%.
<h3>What is percentage?</h3>
It's the ratio of two integers stated as a fraction of a hundred parts. It is a metric for comparing two sets of data, and it is expressed as a percentage using the percent symbol.
We have:
Zoey wants to use her computer tablet throughout a 6-hour flight. Upon takeoff, she uses the tablet for 2 hours and notices that the battery dropped by 33%, from 100% to 67%.
Let's suppose x hours Zoey can expect from the tablet on a full battery charge.
The value of x can be calculated using:
x = (2×100)/33
x = 200/33
x = 6.06 ≈ 6 hours
Thus, 6 hours Zoey can expect from the tablet on a full battery charge if the battery dropped by 33%, from 100% to 67%.
Learn more about the percentage here:
brainly.com/question/8011401
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The minimum value of a function is the place where the graph has a vertex at its lowest point.
There are two methods for determining the minimum value of a quadratic equation. Each of them can be useful in determining the minimum.
(1) By plotting graph
We can find the minimum value visually by graphing the equation and finding the minimum point on the graph. The y-value of the vertex of the graph will be the minimum.
(2) By solving equation
The second way to find the minimum value comes when we have the equation y = ax² + bx + c.
If our equation is in the form y = ax^2 + bx + c, you can find the minimum by using the equation min = c - b²/4a.
The first step is to determine whether your equation gives a maximum or minimum. This can be done by looking at the x² term.
If this term is positive, the vertex point will be a minimum; if it is negative, the vertex will be a maximum.
After determining that we actually will have a minimum point, use the equation to find it.
order of operations
BEMDAS:
B - <em>Brackets</em>
E - <em>Exponents</em>
D - <em>Division</em>
M - <em>Multiplication</em>
A - <em>Addition</em>
S - <em>Subtraction</em>
73 • 7 - 5 = 511 - 5 = 506
All that is needed is a single counter-example.
One counter-example is to multiply the monomial x^3 with the binomial x^7-10x^4
We then get...
x^3*(x^7-10x^4) = x^3*x^7 + x^3*(-10x^4)
x^3*(x^7-10x^4) = x^10 - x^7
The result we get is a binomial as there are still only two terms here. We would need three terms to have a trinomial.
