The x-coordinate of the point which divide the line segment is 3.
Given the coordinates in the figure are J(1,-10) and K(9,2) and the 1:3 is the ratio in which the line segment is divided.
When the ratio of the length of a point from both line segments is m:n, the Sectional Formula can be used to get the coordinate of a point that is outside the line.
To find the x-coordinate we will use the formula x=(m/(m+n))(x₂-x₁)+x₁.
Here, m:n=1:3 and x₁=1 from the point J(1,-10) and x₂=9 from the point K(9,2).
Now, we will substitute these values in the formula, we get
x=(1/(1+3))(9-1)+1
x=(1/4)(8)+(1)
x=8/4+1
x=3
Hence, the x-coordinate of the point that divides the directed line segment from k to j into a ratio of 1:3 is 3 units.
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Answer:
see below
Step-by-step explanation:
y = 8x − 9
y = 4x − 1
Since both equations are equal to y, we can set them equal to each other
8x-9 = 4x-1
Subtract 4x from each side
8x-4x-9 = 4x-4x-1
4x-9 = -1
Add 9 to each side
4x-9+9 = -1+9
4x = 8
Divide each side by 4
4x/4 = 8/4
x=2
Now find y
y = 4x-1
y = 4(2)-1
y = 8-1
y = 7
(2,7)
The point of intersection when the 2 lines are graphed is (2,7)
Answer:
Z<4
Step-by-step explanation:
Answer:
-5
Step-by-step explanation:
We can solve for x
4x = 32
Divide each side by 4
4x/4 = 32/4
x = 8
Now find 35 -5x
35 - 5(8)
35 - 40
-5
The formula to get the multiplicative rate of change is this:
[ f(x2) / f(x1) ] / (x2 - x1)
or
(y2 / y1) / (x2 - x1)
Choosing of the coordinates (-1, 0.8) and (0,2)
MRC = 2/0.8 / (0-(-1)) = 5/2
Using the other coordinates (0,2) and (1,5)
MRC = 5/2 / (1-0) = 5/2
The MRC will be constant per interval.