Group and factor
group y's with y's and z's with z's
(y²-10y)+(10z-yz)
factor
y(y-10)+z(10-y)
force undistribute -1
-y(10-y)+z(10-y)
factor
(10-y)(-y+z)
(z-y)(10-y) or
(y-z)(y-10)
Answer:
tens-or 60
Step-by-step explanation:
the 1 is in the ones place the 6 is in the tens place and the 8 is in the hudreths place.
The polynomial cannot be factored in because it exists prime. Since 112 exists not a perfect square number so we cannot estimate the factors of the given equation.
<h3>What is a quadratic equation?</h3>
In a quadratic equation ax² + bx + c = 0
when (b² - 4ac) exists a perfect square only then we can factorize the equation.
In the given equation x² - 8x - 12 we have to determine the value of
b² - 4ac
From the equation, we get b = -8 and c = -12
b²- 4ac = (-8)² - 4(1)(-12)
= 64 + 48 = 112
Since 112 exists not a perfect square number so we can not estimate the factors of the given equation.
To learn more about quadratic equation refer to:
brainly.com/question/1214333
#SPJ4
Answer:
D
Step-by-step explanation:
8590 x 0.03 = 257.70
._.
Tax is 1.54
Including tax = 39.99
Excluding tax= 38.5
Hope this helps