Answer:
<u><em>y=3/4x+7</em></u>
Step-by-step explanation:
<em><u>You want to find the equation for a line that passes through the point (-4,4) and has a slope of 3/4.
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<em><u>First of all, remember what the equation of a line is:
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<em><u>y = mx+b
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<em><u>Where:
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<em><u>m is the slope, and
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<em><u>b is the y-intercept
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<em><u>To start, you know what m is; it's just the slope, which you said was 3/4. So you can right away fill in the equation for a line somewhat to read:
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<em><u>y=3/4x+b.
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<em><u>Now, what about b, the y-intercept?
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<em><u>To find b, think about what your (x,y) point means:
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<em><u>(-4,4). When x of the line is -4, y of the line must be 4.
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<em><u>Because you said the line passes through this point, right?
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<em><u>Now, look at our line's equation so far: . b is what we want, the 3/4 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (-4,4).
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<em><u>So, why not plug in for x the number -4 and for y the number 4? This will allow us to solve for b for the particular line that passes through the point you gave!.
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<em><u>(-4,4). y=mx+b or 4=3/4 × -4+b, or solving for b: b=4-(3/4)(-4). b=7.</u></em>
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<em><u>hope this answers your question sorry it's soo long i just like writing long stuff have a great day!!</u></em>
