Question

Simply the function f(x)=7(3Square root 54^x)

Answer 1

Answer:

54 = 2 × 3 × 3 × 3 = 2 × 3³

$f(x) = 7(\sqrt[3]{54})^x$

$f(x) = 7(\sqrt[3]{3^3 \times 2})^x$

$f(x) = 7(3\sqrt[3]{2})^x$

Initial value: x = 0

$f(0) = 7(3\sqrt[3]{2})^0$

$f(0) = 7(1)$

$f(0) = 7$

The initial value is 7.

The domain is all real numbers.

The range is all real numbers greater than zero.