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andrew-mc [135]
2 years ago
8

First Person = Brainliest.

Mathematics
2 answers:
NeX [460]2 years ago
4 0

Answer:

1080

___ rode a plane for 5^2 miles on a flight to ___. She then took a flight to ___ which was 5^4 miles. How much further did she fly on the second flight?

you can decide where she went and what her name was.

Step-by-step explanation:

6^3 = 213

6^4 = 1296

1296 - 216 = 1080

Goryan [66]2 years ago
3 0
First we need to figure out the exponents.

6^3 is the same as 6 x 6 x 6 = 216
6^4 is the same as 6 x 6 x 6 x 6 = 1,296

(These are easy to figure on a calculator)

Now that we know the full amount of miles she drove, we subtract the two numbers.

In the first month she drove 216 miles
In the second month she drove 1,296 miles

Month 2 - month 1 = 1,296 - 216 = 1,080.

Mali drove 1,080 more miles in the second month than in the first month.

Hope this helps!
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How many 6-digit numbers can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, if repetitions of digits are allowed?
sveta [45]
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Another way of thinking about this is to just count up to 999,999.  Obviously there are 999,999 different numbers here.  But since our number has to have 6 digits in them, we have to delete 99,999 numbers.  Thus there are 900,000 different numbers.
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anyanavicka [17]

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How many 3-digit even numbers are that begin with either 5 or 6?
mojhsa [17]
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8 0
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Read 2 more answers
Question below
Ksivusya [100]

Answer:

m \times H=\left[\begin{array}{c c c}\boxed{-9} & \boxed{36} & \boxed{-\dfrac{9}{2}}\end{array}\right]

Step-by-step explanation:

<u>Calculate the value of m</u>

Given:

3\left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]=\dfrac{2}{3}m \times \left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]

Therefore:

\implies 3=\dfrac{2}{3}m

\implies m=3 \times \dfrac{3}{2}

\implies m=\dfrac{9}{2}

<u>Calculate the value of H</u>

Given:

\left(H+ \left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]\right)+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]=\left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]+\left(\left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]\right)

Therefore:

\implies H= \left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]

<u />

<u>Calculating m × H</u>

<u />

<u />\implies m \times H=\dfrac{9}{2} \times \left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]

<u />\implies m \times H=\left[\begin{array}{c c c}\dfrac{9}{2}(-2) & \dfrac{9}{2}(8) & \dfrac{9}{2}(-1)\end{array}\right]

\implies m \times H=\left[\begin{array}{c c c}-9 & 36 & -\dfrac{9}{2}\end{array}\right]<u />

7 0
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