To solve for this, we need to find for the value of x
when the 1st derivative of the equation is equal to zero (or at the
extrema point).
So what we have to do first is to derive the given
equation:
f (x) = x^2 + 4 x – 31
Taking the first derivative f’ (x):
f’ (x) = 2 x + 4
Setting f’ (x) = 0 and find for x:
2 x + 4 = 0
x = - 2
Therefore the value of a is:
a = f (-2)
a = (-2)^2 + 4 (-2) – 31
a = 4 – 8 – 31
a = - 35
Answer:
x=0,![\sqrt[6]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B5%7D)
Decimal form,
x=0,1.30766048......
Step-by-step explanation:
x
=
x-=0
(take x as a common factor)
x(-
)=0
So,
x=0 and -=0
for 
-=0
(add for both sides)
=
x=![\sqrt[3]{\sqrt[2]{5} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Csqrt%5B2%5D%7B5%7D%20%7D)
(multiply 3 by 2)
x=
So,
x=0,
Answer: 150
Step-by-step explanation: so when you want a whole amount of something you want to the 100% of it because 100% is the whole thing right? Well right now you only have 20% so how much do you need to multiply that by to get 100%?? Well that answer is 5. Okay so now since $30 is 20% but we wanna get it to 100% multiply it by 5 so 30x5 which is 150
