I'm not sure if this is the easiest way of doing this, but it surely work.
Let the base of the triangle be AB, and let CH be the height. Just for reference, we have
Moreover, let CH=y and BC=z
Now, AHC, CHB and ABC are all right triangles. If we write the pythagorean theorem for each of them, we have the following system
If we solve the first two equations for y squared, we have
And we can deduce
So that the third equation becomes
(we can't accept the negative root because negative lengths make no sense)
36/54 = x/100
54x = 100 * 36
54x = 3600
x = 3600 ÷ 54
x = 66.666666.... so 66.67
First put it into a proportion and then cross multiply. After that you divide both sides by 54 to get x alone which gives you 66.66666 which is rounded to 66.67
Answer: 66.67%
4.45 if you were trying to accurately show the decimal of acers of area halfway across the park.
Answer:
57
Step-by-step explanation:
1) According to PEMDAS, <em>multiply </em>first: 27+ 5x6= 27+30
2) Then <em>add</em>: 27+30=57
Answer:
-3072
Step-by-step explanation:
ar^(n-1)
a is the first term.
r is the common ratio.
3(-4)^(6-1)
3(-4)^5
3(-1024)
= -3072
The 6th term of the geometric sequence is -3072.
