The correct relation for the sea gull population is: P(t) = 5.3t^(11/7)
Answer:
d. about 66.5 hundred thousand
Step-by-step explanation:
Given that :
P(t) = 5.3t^(11/7)
Population, P is in hujdred thousand ; t = number of years
Population after 5 years ;
t = 5
P(5) = 5.3 * 5^(11/7)
P(5) = 5.3 * 5^1.5714285
P(5) = 5.3 * 12.542422
P(5) = 66.474840
P(5) = 66.5 (approximately)
Hence, population after 5 years will be about 66.5 hundred thousand.
Step 1: -6a + 3 = -3(2a - 1)
Step 2: -6a + 3 = -3(2a) + 3(1)
Step 3: -6a + 3 = -6a + 3
Step 4:+6a +6a
Step 5: 3 = 3
The variable of x is equal to Any infinite number.
Answer:
Step-by-step explanation:
https://drive.google.com/open?id=1QAvmjDjuwgFX0mUdHlWmqMSCJcOVMw2X
The first thing we are going to do is find the area of the field. To do this we are going to use the area of a square formula:

Were

is the area in square kilometers

is one of the sides of the square
We know for our problem that the side lengths of the field are 0.9 kilometers, so

. Lets replace that value in our formula to find

:

Now, to find the population density of the filed, we are going to use the population density formula:

where

is the population density in <span>in burrows per square kilometer
</span>

is the number of burrows

is the are of the field
We know that

and

, so lets replace those values in our formula:


We can conclude that the <span>density of prairie dog burrows is approximately
2444 burrws per square kilometer.</span>
Answer:
Step-by-step explanation:
Given: quadrilateral ABCD inscribed in a circle
To Prove:
1. ∠A and ∠C are supplementary.
2. ∠B and ∠D are supplementary.
Construction : Join AC and BD.
Proof: As, angle in same segment of circle are equal.Considering AB, BC, CD and DA as Segments, which are inside the circle,
∠1=∠2-----(1)
∠3=∠4-----(2)
∠5=∠6-------(3)
∠7=∠8------(4)
Also, sum of angles of quadrilateral is 360°.
⇒∠A+∠B+∠C+∠D=360°
→→∠1+∠2+∠3+∠4+∠5+∠6+∠7+∠8=360°→→→using 1,2,3,and 4
→→→2∠1+2∠4+2∠6+2∠8=360°
→→→→2( ∠1 +∠6) +2(∠4+∠8)=360°⇒Dividing both sides by 2,
→→→∠B + ∠D=180°as, ∠1 +∠6=∠B , ∠4+∠8=∠B------(A)
As, ∠A+∠B+∠C+∠D=360°
∠A+∠C+180°=360°
∠A+∠C=360°-180°------Using A
∠A+∠C=180°
Hence proved.
credit: someone else