Question

Given that f(x)= x^2-3/2 find f^-1(x)

Answer 1

Answer:

$\bold{f(x)=-\frac{1}{2}}$

Step-by-step explanation:

$f(x)= x^2-\frac{3}{2}$              replace x with -1

$f(x)= -1^2-\frac{3}{2}$           solve exponents

-1² = -1 × -1 = 1

$f(x)= 1-\frac{3}{2}$                subtract

$\bold{f(x)=-\frac{1}{2}}$