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tatyana61 [14]
3 years ago
6

Simplify the expression

" title="10.8 + - 7.6 + 10.2h + 9.2" alt="10.8 + - 7.6 + 10.2h + 9.2" align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
Dimas [21]3 years ago
6 0
You need to combine like terms. The like terms in this equation are 10.8, -7.6, and 9.2. 10.8-7.6+9.2 = 12.4. 10.2h can’t be combined with anything else. So the final answer is:

12.4 + 10.2h
never [62]3 years ago
3 0
9.6+10.2h is the correct answer

10.8 + -7.6 + 10.2h+9.2
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A drawer contains quarters and nickels. There are 200 total coins valuing $30.00. Think about a system of equations that can be
Margaret [11]

Answer:

100

Step-by-step explanation:

Let n and q represent the numbers of nickels and quarters, respectively. A suitable system of equations is ...

  n + q = 200 . . . . . . there are 200 coins in the drawer

  5n +25q = 3000 . . .their value is $30.00

For mixture problems like this, it is often a good idea to substitute for the variable representing the contributor of lower value. That is, we want to write an expression for n that we can use for substitution.

Using the first equation to solve for n, ...

  n = 200 - q

Substituting this into the second equation gives ...

  5(200 -q) +25q = 3000

  1000 +20q = 3000 . . . . . . simplify

  20q = 2000 . . . . . . . . . . . . subtract 1000

  q = 100 . . . . . . . . . . . . . . . . divide by 20

  n = 200 -q = 100 . . . . . . . . the number of nickels, as we want

_____

<em>Comment on the solution</em>

We solved for q, then had to do an extra step to find the value of n that the problem asks for. Had we written q = 200-n and used that for substitution, we would have ended with the equation -20n = -2000. This would give the answer for n directly (with no additional steps required).

Sometimes working with negative numbers is uncomfortable or results in errors, so we chose to use the solution method that would avoid negative numbers.

___

<em>Comment on the problem statement</em>

We are told about coins in a <u>drawer</u>, and we are asked about coins in a <u>jar</u>. There is not enough information to answer the question asked. We have had to assume that both refer to the same quantity of coins—an assumption that is not supported by anything in the problem statement.

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Solve the following systems of equations by substitution method.
Anuta_ua [19.1K]

Answer:

1) x = 3 and y = -2

2) x = 2 and y = 1

3) x = -2 and y = -1

4) x = 3 and y = 2

5) x = 2

6) x = 2 and y = -3

7) x = 4 and y = 3

8) x = -3 and y = -6

Step-by-step explanation:

1. Answer :

y = -2

4x - 3y = 18 ----(1)

Substitute y = -2 in (1).

4x - 3(-2) = 18

4x + 6 = 18

Subtract 6 from both sides.

4x = 12

Divide both sides by 4.

x = 3

So,

x = 3 and y = -2

2. Answer :

y = 6x - 11 ----(1)

2x + 3y = 7 ----(2)

Substitute y = 6x - 11 in (2).

2x + 3(6x - 11) = 7

2x + 18x - 33 = 7

20x - 33 = 7

Add 33 to both sides.

20x = 40

Divide both sides by 20.

x = 2

Substitute x = 2 in (1).

y = 6(2) - 11

= 12 - 11

= 1

So,

x = 2 and y = 1

3. Answer :

x = -3y - 5 ----(1)

4x - 5y = -3 ----(2)

Substitute x = -3y + 5 in (2).

4(-3y - 5) - 5y = -3

-12y - 20 - 5y = -3

-17y - 20 = -3

Add 20 to both sides.

17y = -17

Divide both sides by 17.

y = -1

Substitute y = -1 in (1).

x = -3(-1) - 5

= 3 - 5

= -2

So,

x = -2 and y = -1

4. Answer :

x = 5y - 7 ----(1)

-2x - 3y = -12 ----(2)

Substitute x = 5y - 7 in (2).

-2(5y - 7) - 3y = -12

-10y + 14 - 3y = -12

-13y + 14 = -12

Subtract 14 from both sides.

-13y = -26

Divide both sides by -13.

y = 2

Substitute y = 2 in (1).

x = 5(2) - 7

= 10 - 7

= 3

So,

x = 3 and y = 2

5. Answer :

5x + 3y - 8 = 0 ----(1)

2x - 3y - 6 = 0 ----(2)

Solve for 3y in (1).

5x + 3y - 8 = 0

Subtract 5x from both sides.

3y - 8 = -5x

Add 8 to both sides.

3y = -5x + 8

Substitute 3y = -5x + 8 in (2).

2x - (-5x + 8) - 6 = 0

2x + 5x - 8 - 6 = 0

7x - 14 = 0

Add 14 to both sides.

7x = 14

Divide both sides by 7.

x = 2

6. Answer :

x - 3y - 11 = 0 ----(1)

5x + y - 7 = 0 ----(2)

Solve for x in (1).

x - 3y - 11 = 0

Subtract 3y and 11 to both sides.

x = 3y + 11 ----(3)

Substitute x = 3y + 11 in (2).

5(3y + 11) + y - 7 = 0

15y + 55 + y - 7 = 0

16y + 48 = 0

Subtract 48 from both sides.

16y = -48

Divide both sides by 16.

y = -3

Substitute y = -3 in (3).

x = 3(-3) + 11

= -9 + 11

= 2

So,

x = 2 and y = -3

7. Answer :

2x - 3y = -1 ----(1)

y = x - 1 ----(2)

Substitute y = x - 1 in (1).

2x - 3(x - 1) = -1

2x - 3x + 3 = -1

-x + 3 = -1

Subtract 3 from both sides.

-x = -4

Multiply both sides by -1.

x = 4

Substitute x = x in (3).

y = 4 - 1

= 3

So,

x = 4 and y = 3

8. Answer :

-4x + y = 6 ----(1)

-5x - y = 21 ----(2)

Solve for y in (1).

-4x + y = 6

Add 4x to both sides.

y = 4x + 6 ----(3)

Substitute y = 4x + 6 in (2).

-5x - (4x + 6) = 21

-5x - 4x - 6 = 21

-9x - 6 = 21

Add 6 to both sides.

-9x = 27

Divide both sides by -9.

x = -3

Substitute x = -3 in (3).

y = 4(-3) + 6

= -12 + 6

= -6

So,

x = -3 and y = -6

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Thank You!

Answered by: ms115

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3 years ago
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borishaifa [10]

Answer:

45

Step-by-step explanation:

Plug in the values into the equation

4(12) - 3

48 - 3 = 45

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If L=√(x^2+y^2), dx/dt =-4, dy/dt=3, find dL/dt when x=4 and y=3
yulyashka [42]

Hello,

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