Answer:
beta perfecto esto muy chever
Answer:
10
Step-by-step explanation:
Answer
a) y | p(y)
25 | 0.8
100 | 0.15
300 | 0.05
E(y) = ∑ y . p(y)
E(y) = 25 × 0.8 + 100 × 0.15 + 300 × 0.05
E(y) = 50
average class size equal to E(y) = 50
b) y | p(y)
25 | 
100 | 
300 | 
E(y) = ∑ y . p(y)
E(y) = 25 × 0.4 + 100 × 0.3 + 300 × 0.3
E(y) = 130
average class size equal to E(y) = 130
c) Average Student in the class in a school = 50
Average student at the school has student = 130
Answer:
D
Step-by-step explanation:
out of the choices
A) 2x-y=-2
3x+2y=-10
B) x+4y=3
2x+5y=3
C) 2x+3y=5
x-4y=-14
D) 3x+4y=15
x+y=5
only the system in D has a solution of x=5 and y=0
solve by substitution x+y=5 so x=5-y
plug into the other equation so 3(5-y)+4y=15
distribute 15-3y+4y=15 then minus 15 on both sides and combine like terms
so y=0 then put that value back into the other equation
so x+y=5 equals x+0=5 so x=5 this means the solution to the system of equations is the point (5,0)
Hope this helps! :)
Answer:
huh????
Step-by-step explanation:
what did you try to say
