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KengaRu [80]
2 years ago
6

With negative numbers, how do we know when the negative sign indicates that it is a subtraction or it is a negative number?

Mathematics
1 answer:
Paha777 [63]2 years ago
5 0

Answer:

its always a negitive number subtraction is just adding a negitive number

5-3 is 5+(-3)

(−5+7×1)−9×5

(−5+7)−45

2-45

-43

Hope This Helps!!!

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What is the polynomial is factored form please help
Eddi Din [679]

Answer:

c

Step-by-step explanation:

divide it by 5x. the rest of this is all just to fill up the space that I have to have to put the answer you can ignore it

5 0
3 years ago
It took Margie 2 1/4hours to write a 1 1/2 page research paper . What was her hourly writing rate
WARRIOR [948]


Margie would take 1 hour and 30 minutes to write 1 page of her research paper. Think of it like a proportion:

2.25/ 1.5 = x/1

2.25 is the 2 1/4 converted which is the amount of hours she took.

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1 on the right side of the proportion represents  1 page.

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3 years ago
If the radius of a cylinder is 3 centimeters, then will the area of one of the circular bases is 18.84 square centimeters
luda_lava [24]
NO, the area would be 28.26.

4 0
3 years ago
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Find the circumference and the area of a circle with radius 4 cm <br><br> Please help!
Alexus [3.1K]
Circumference: 2 * pi * r
pi = 3.14, r = 4
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3 years ago
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Find the intervals on which​ f(x) is​ increasing, the intervals on which​ f(x) is​ decreasing, and the local extrema. f (x )equa
Kaylis [27]

Answer:

f(x) is increasing in the intervals (-∞,-4) and (9,∞)

f(x) is decreasing in the ingercal (-4,9)

The local extrema is:

local max at (-4,496)

and local min at (9,-1701)

Step-by-step explanation:

In order to solve this problem we must start by finding the derivative of the provided function, which we can find by using the power rule.

if f(x)=ax^{n} then f'(x)=anx^{n-1}

so we get:

f(x)=2x^{3}-15x^{2}-216x

f'(x)=6x^{2}-30x-216

in order to find the critical points we mus set the derivative equal to zero, since the local max an min will happen when the slope of the tangent line to the given point is zero, so we get:

6x^{2}-30x-216=0

we can solve this by factoring, so let's factor that equation:

6(x+4)(x-9)=0

we can now set each of the factors equal to zero so we get:

x+4=0 and x-9=0

when solving each for x we get that:

x=-4 and x=9

These are our critical points, now we can build the possible intervals we are going to use to determine where the function will be increasing and where it will be decreasing:

(-∞,-4), (-4,9) and (9,∞)

so now we need to test these intervals in the derivative to see if the graph will be increasing or decreasing in the given intervals. So let's pick x=-5 for the first one, x=0 for the second one and x=10 for the third one.

When evaluating them into the first derivative we get that:

f'(-5)=84, this is a positive answer so it means that the function is increasing in the interval (-∞,--4)

f'(0)=-216, this is a negative anser so it means that the function is decreasing in the interval (-4,9)

f'(10)=84, this is a positive answer so it means that the function is increasing in the interval (9,∞)

Now, for the local extrema, we can see that at x=-4, the function it's increasing on the left of this point while it's decreasing to the right, which means that there will be a local maximum at x=-4, so the local max is the point (-4,496)

We can see that at x=9, the function it's decreasing on the left of this point while it's increasing to the right, which means that there will be a local minimum at x=-9, so the local min is the point (9,-1701)

7 0
3 years ago
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