Solve for n. 2n − 3/5=5

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Alina [70]

Answer:

Mean=13.22

Median=13.05

Standar deviation=3.51

The mean is a measure of central tendency in a probabilistic sense. Matematically speaking, it can be calculated as the average of the elements that conform a set of numbers. It is important because it provides you with information about a dataset without having to know every value of your data. As an example, if you have a sample of the age of school teachers, the mean age of teachers will tell you what is the average age among all the teachers in the sample.It can be calculated like this: $\frac{1}{n} \times \sum x = \frac{1}{n} \times (12+12.5+18.2+13.6+15.3+7.7) = 13.22$
The median value results from ordering the dataset in an ascending way, from the smallest to the greatest, and then determining which value divides the sample ordered in this way, in half. It is an other measure of central tendency and it helps you to know about the balance of your data. In the example provided before, if the median age of teachers is 45, you know that half of teachers are older than 45, and the other half is younger. When dealing with a finite set of numbers, the median’s value will depend on the characteristic of the sample. If there is an odd number of observations, the median value will be the middle value. On the other hand, if there is an even number of observations, the median will be the average between the two middle values. In the exercise, this value is calculated as the average between 12.5 and 13.6, which results in 13.05.
Standar deviation is a measure of dispersion around the mean value. Its value is an indicator of how near are the observations in the sample, from the mean. A low standard deviation imply that the observations in your dataset are closed to the mean value. In terms of the teachers’ example, if the mean is 50 and the standard deviation is 2, many of the teachers in your datasets are between 48-52 years old. Following this example, if the standard deviation was 10 and the mean 50, most of the teachers would be between 40 and 60 years old (mean plus and less 10 years). The lowest the standard deviation, the more informative the mean: when the standard deviation is small, the values of the sample are closer to the mean. To obtain the standar deviation value one should use the following equation: $s=\sqrt{\frac{1}{n-1} \times \sum{ (x_{i} - \bar{x})^{2} } \\$ , where $\bar{x}$ is the mean value that you calculated before, and "n" is the number of observations in the sample.

3 0

3 years ago

This one is super confusing i will give extra points

kondaur [170]

Answer:

volume=12m

Step-by-step explanation:

width*length*height=volume

4m=width

3m=height

4m*3m=12m

12m=volume

8 0

3 years ago

-0.8662866239 . . . is: rational irrational

djverab [1.8K]

Answer:

irrational, it can't be written as a fraction

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Which is a flat surface with no thickness that contains many lines and extends without end in the directions of all its lines?

Lina20 [59]

Answer: A plane

This needs to be 20 characters long so this is ok

3 0

3 years ago

The average yield of the standard variety off soybeans per acre on a farm in a region is 48.8 bushels per acre, with a standard

I am Lyosha [343]

Answer:

$z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3$

$p_v =P(Z>2.3)=1-P(Z$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.

Step-by-step explanation:

1) Data given and notation

$\bar X=53.4$ represent the sample mean

$\sigma=12$ represent the population standard deviation assumed

$n=36$ sample size

$\mu_o =48.8$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

2) State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is higher than 48.8, the system of hypothesis would be:

Null hypothesis: $\mu \leq 48$

Alternative hypothesis: $\mu > 48$

Since we assume that know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

3) Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3$

4)P-value

Since is a right tailed test the p value would be:

$p_v =P(Z>2.3)=1-P(Z$

5) Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.

3 0

3 years ago