We have that
<span>A).Formulate a recursive sequence modeling the number of grams after n hours.
a(n) = 0.75*a(n-1)
</span>B) .Use the model to calculate the amount of contaminants after the third hour of the experiment.
<span> for the first hour
</span>a(1) = 0.75*a(0)
<span>a0=400 g
a1=(3/4)400 = 300 g
for the second hour
</span>a(2) = 0.75*a(1)
<span>a1=300 g
a2=(3/4)300 = 900/4 g
for the third hour
</span>a(3) = 0.75*a(2)
<span>a2=900/4 g
(3/4)900/4 = 2700/16 = 168.75 g
the answer is </span>168.75 g
C
4/8 equals 1/2 the rest are 1/2 but 12/36 is 1/3
Answer:
I believe A has the proper quartiles and the approx median marked correctly
Step-by-step explanation:
Let each side perpendicular to the wall be x
The parallel to the wall will be 320-2x
the area will be:
A(x)=x(320-2x)
A(x)=320x-2x^2
This is a quadratic with a =-2 and b=320
Maximum area will occur where x=-b/2a
=-320/(-2*2)
=80 ft
thus the width will be 80 ft and the length will be:
length=320-2*80=160 ft
Vertex is -1,2.................
