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3 years ago

Solve this system of equations using the substitution method.

Mathematics

1 answer:

Bingel [31]3 years ago

5 0

Answer:

x = 1.2

y = 6.6

Step-by-step explanation:

1) y= -2x+9

2) 8x-3=y

Substitute y in equation 1 using y in equation 2.

8x - 3 = -2x + 9

+ 3 on both sides

8x = -2x + 12

+ 2x on both sides

10x = 12

x = 1.2

To find y, plug in x

8x - 3 = y

9.6 - 3 = y

6.6 = y

Hope this helps :)

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Which statement is true about this function h(x) = 2^x-5

Marysya12 [62]

Answer:

$\frac{1}{32} x$

Step-by-step explanation:

3 0

3 years ago

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What is the area of this triangle ?

oee [108]

Answer:

Area of triangle is 9.88 units^2

Step-by-step explanation:

We need to find the area of triangle

Given E(5,1), F(0,4), D(0,8)

We will use formula:

$Area\,\,of\,\,triangle =\sqrt{s(s-a)(s-b)s-c)} \\where\,\, s = \frac{a+b+c}{2}$

We need to find the lengths of side DE, EF and FD

Length of side DE = a = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side DE = a = $=\sqrt{(5-0)^2+(1-8)^2}\\=\sqrt{(5)^2+(-7)^2}\\=\sqrt{25+49}\\=\sqrt{74}\\=8.60$

Length of side EF = b = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side EF = b = $=\sqrt{(0-5)^2+(4-1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\=5.8$

Length of side FD = c = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side FD = c = $=\sqrt{(0-0)^2+(8-4)^2}\\=\sqrt{(0)^2+(4)^2}\\=\sqrt{0+16}\\=\sqrt{16}\\=4$

so, a= 8.60, b= 5.8 and c = 4

s = a+b+c/2

s= 8.6+5.8+4/2

s= 9.2

Area of triangle= $=\sqrt{s(s-a)(s-b)s-c)}\\=\sqrt{9.2(9.2-8.6)(9.2-5.8)(9.2-4)}\\=\sqrt{9.2(0.6)(3.4)(5.2)}\\=\sqrt{97.5936}\\=9.88$

So, area of triangle is 9.88 units^2

4 0

3 years ago

Anybody know the answer?

expeople1 [14]

Y=x-2+3
I put x-2 because when graphing it's the opposite so it would technically be x+2
Then the +3 for the y chords which go up by 3 ! if this is wrong then try Y= (x-2)+3

8 0

3 years ago

Find the value of a answers: a:15 b:14 c:19 d:16

Paul [167]

Answer:

6a+10= 3a+55

6a-3a= 55-10

3a= 45

a= 45/3

a= 15

The answer is (A) 15

Hope this helps^°^

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3 years ago

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Find the area of the shaded region.

kolbaska11 [484]

Answer:

$\boxed{ \tt\longrightarrow \: Area \: Of \: Shaded \: region \: =\boxed{ \tt 39 \: in²}}$

Step-by-step explanation:

Given:

The Dimensions of Parallelogram are 12 in.(Base) and 7 in.(Height)

And,

The Dimensions of Rectangle are 9 in.(Length) and 5 in.(Breadth).

To Find:

The Area of Shaded region

Solution:

When the dimensions of parallelogram and the dimensions of rectangle are given, we need to find the Shaded region using this formula:

$\boxed{\tt \longrightarrow Area = (Parallelogram - Rectangle)}$

We know that the formula of Parallelogram is base*height[b×h] and the formula of rectangle is length*breadth[l*b] .

$\tt\longrightarrow \: Area =B×h-l×b$

Put their values accordingly:

$\longrightarrow \tt Area = (12 \times 7 - 9 \times 5)in {}^{2}$

Simplify it.

[Follow BODMAS Rule strictly while simplifying]

$\tt\longrightarrow \: Area = (84 - 45 ) in {}^{2}$

$\tt\longrightarrow \: Area = 39 \: {in}^{2}$

Hence, the Area of Shaded region would be 39 in² or 39 sq. in. .

$\rule{225pt}{2pt}$

I hope this helps!

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2 years ago

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