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Crank
3 years ago
8

Solve this system of equations using the substitution method.

Mathematics
1 answer:
Bingel [31]3 years ago
5 0

Answer:

x = 1.2

y = 6.6

Step-by-step explanation:

1) y= -2x+9

2) 8x-3=y

Substitute y in equation 1 using y in equation 2.

8x - 3 = -2x + 9

+ 3 on both sides

8x = -2x + 12

+ 2x on both sides

10x = 12

x = 1.2

To find y, plug in x

8x - 3 = y

9.6 - 3 = y

6.6 = y

Hope this helps :)

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\frac{1}{32} x

Step-by-step explanation:

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What is the area of this triangle ?
oee [108]

Answer:

Area of triangle is 9.88 units^2

Step-by-step explanation:

We need to find the area of triangle

Given E(5,1), F(0,4), D(0,8)

We will use formula:

Area\,\,of\,\,triangle =\sqrt{s(s-a)(s-b)s-c)} \\where\,\, s = \frac{a+b+c}{2}

We need to find the lengths of side DE, EF and FD

Length of side DE = a = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side DE = a = =\sqrt{(5-0)^2+(1-8)^2}\\=\sqrt{(5)^2+(-7)^2}\\=\sqrt{25+49}\\=\sqrt{74}\\=8.60

Length of side EF = b = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side EF = b = =\sqrt{(0-5)^2+(4-1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\=5.8

Length of side FD = c = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side FD = c = =\sqrt{(0-0)^2+(8-4)^2}\\=\sqrt{(0)^2+(4)^2}\\=\sqrt{0+16}\\=\sqrt{16}\\=4

so, a= 8.60, b= 5.8 and c = 4

s = a+b+c/2

s= 8.6+5.8+4/2

s= 9.2

Area of triangle==\sqrt{s(s-a)(s-b)s-c)}\\=\sqrt{9.2(9.2-8.6)(9.2-5.8)(9.2-4)}\\=\sqrt{9.2(0.6)(3.4)(5.2)}\\=\sqrt{97.5936}\\=9.88

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4 0
3 years ago
Anybody know the answer?
expeople1 [14]
Y=x-2+3
I put x-2 because when graphing it's the opposite so it would technically be x+2
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3 years ago
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Answer:

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Answer:

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Step-by-step explanation:

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\rule{225pt}{2pt}

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