Answer:
6.64 seconds
Step-by-step explanation:
Given that:
Distance between roof of the terminal and ground = 709 feet
A bucket was dropped from the roof.
To find:
The time taken by the bucket to hit the ground?
Solution:
Distance traveled,  = 709 feet
 = 709 feet
Initial velocity of the bucket,  = 0 feet/sec (because initially it was at rest)
 = 0 feet/sec (because initially it was at rest)
Acceleration of the bucket will be equal to acceleration due to gravity i.e.
 or 32.1741
 or 32.1741 
Let the time taken is  seconds.
 seconds.
Formula for distance is given as:

Putting all the values:

 
        
             
        
        
        
Answer:
y = 15x
Step-by-step explanation:
Given x and y are in direct variation then the equation relating them is
y = kx ← k is the constant of variation
To find k use the condition x = 2, y = 30, then
30 = 2k ( divide both sides by 2 )
15 = k
y = 15x ← equation of variation
 
        
                    
             
        
        
        
So... hmm bear in mind, when the boat goes upstream, it goes against the stream, so, if the boat has speed rate of say "b", and the stream has a rate of "r", then the speed going up is b - r, the boat's rate minus the streams, because the stream is subtracting speed as it goes up
going downstream is a bit different, the stream speed is "added" to boat's
so the boat is really going faster, is going b + r
notice, the distance is the same, upstream as well as downstream
thus   
![\bf \begin{cases}
b=\textit{rate of the boat}\\
r=\textit{rate of the river}
\end{cases}\qquad thus
\\\\\\

\begin{array}{lccclll}
&distance&rate&time(hrs)\\
&----&----&----\\
upstream&48&b-r&4\\
downstream&48&b+4&3
\end{array}
\\\\\\

\begin{cases}
48=(b-r)(4)\to 48=4b-4r\\\\
\frac{48-4b}{-4}=r\\
--------------\\
48=(b+r)(3)\\
-----------------------------\\\\
thus\\\\
48=\left[ b+\left(\boxed{\frac{48-4b}{-4}}\right) \right] (3)
\end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%0Ab%3D%5Ctextit%7Brate%20of%20the%20boat%7D%5C%5C%0Ar%3D%5Ctextit%7Brate%20of%20the%20river%7D%0A%5Cend%7Bcases%7D%5Cqquad%20thus%0A%5C%5C%5C%5C%5C%5C%0A%0A%5Cbegin%7Barray%7D%7Blccclll%7D%0A%26distance%26rate%26time%28hrs%29%5C%5C%0A%26----%26----%26----%5C%5C%0Aupstream%2648%26b-r%264%5C%5C%0Adownstream%2648%26b%2B4%263%0A%5Cend%7Barray%7D%0A%5C%5C%5C%5C%5C%5C%0A%0A%5Cbegin%7Bcases%7D%0A48%3D%28b-r%29%284%29%5Cto%2048%3D4b-4r%5C%5C%5C%5C%0A%5Cfrac%7B48-4b%7D%7B-4%7D%3Dr%5C%5C%0A--------------%5C%5C%0A48%3D%28b%2Br%29%283%29%5C%5C%0A-----------------------------%5C%5C%5C%5C%0Athus%5C%5C%5C%5C%0A48%3D%5Cleft%5B%20b%2B%5Cleft%28%5Cboxed%7B%5Cfrac%7B48-4b%7D%7B-4%7D%7D%5Cright%29%20%5Cright%5D%20%283%29%0A%5Cend%7Bcases%7D)
solve for "r", to see what the stream's rate is
what about the boat's? well, just plug the value for "r" on either equation and solve for "b"
 
        
        
        
The answer to -7 +11 -6 + 8 =6
        
             
        
        
        
Answer:
Step-by-step explanation:
3(9x - 14/3x + 4 - 1 ≥ 2)
27x - 14x + 12 - 3 ≥ 6
13x + 9 ≥ 6
13x ≥ -3
x ≥ -3/13