3 years ago

Please help with number one

1 answer:

5 0

1:yes 2:no 3:yes that's what it should be.

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natali 33 [55]

w/–3 + 14 = 5

⇛ w/–3 = 5 – 14

⇛ w/–3 = – 11

⇛ w = –11 × (–3)

⇛ w = 33

7 0

3 years ago

Mashcka [7]

1,725 yards, because 575×3=1,725. Or 575+575+575=1,725

8 0

3 years ago

fredd [130]

$\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

$\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

so the ODE is indeed exact and there is a solution of the form $F(x,y)=C$ . We have

$\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)$

$\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)$

$f'(y)=0\implies f(y)=C$

$\implies F(x,y)=x^2y^3+\ln(x+y^2)=C$

With $y(1)=2$ , we have

$8+\ln9=C$

$\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}$

8 0

3 years ago

maria [59]

Answer:

Step-by-step explanation:

4 0

2 years ago

DerKrebs [107]

I’m pretty sure the answer is c

8 0

3 years ago