Question

The average of two numbers is 70. If one of the number is 32, what is the 2nd number?​

Answer 1

Let’s think, 1st Number= x, 2nd Number=y

Let’s think, 1st Number= x, 2nd Number=yAccording to question, x+y=70 → (i) ; x=2y+10 →(ii)

Let’s think, 1st Number= x, 2nd Number=yAccording to question, x+y=70 → (i) ; x=2y+10 →(ii)Let’s put Equation (i) in (ii),

Let’s think, 1st Number= x, 2nd Number=yAccording to question, x+y=70 → (i) ; x=2y+10 →(ii)Let’s put Equation (i) in (ii),Here, 2y+10+y=70

Let’s think, 1st Number= x, 2nd Number=yAccording to question, x+y=70 → (i) ; x=2y+10 →(ii)Let’s put Equation (i) in (ii),Here, 2y+10+y=70or, 3y+10=70

Let’s think, 1st Number= x, 2nd Number=yAccording to question, x+y=70 → (i) ; x=2y+10 →(ii)Let’s put Equation (i) in (ii),Here, 2y+10+y=70or, 3y+10=70or, 3y=70–10=60

Let’s think, 1st Number= x, 2nd Number=yAccording to question, x+y=70 → (i) ; x=2y+10 →(ii)Let’s put Equation (i) in (ii),Here, 2y+10+y=70or, 3y+10=70or, 3y=70–10=60or, y= 60/30

Let’s think, 1st Number= x, 2nd Number=yAccording to question, x+y=70 → (i) ; x=2y+10 →(ii)Let’s put Equation (i) in (ii),Here, 2y+10+y=70or, 3y+10=70or, 3y=70–10=60or, y= 60/30Therefore, y=20

Let’s think, 1st Number= x, 2nd Number=yAccording to question, x+y=70 → (i) ; x=2y+10 →(ii)Let’s put Equation (i) in (ii),Here, 2y+10+y=70or, 3y+10=70or, 3y=70–10=60or, y= 60/30Therefore, y=20Now we’ll put y’s value in equation (i),

Let’s think, 1st Number= x, 2nd Number=yAccording to question, x+y=70 → (i) ; x=2y+10 →(ii)Let’s put Equation (i) in (ii),Here, 2y+10+y=70or, 3y+10=70or, 3y=70–10=60or, y= 60/30Therefore, y=20Now we’ll put y’s value in equation (i),Here, x=2*20+10

Let’s think, 1st Number= x, 2nd Number=yAccording to question, x+y=70 → (i) ; x=2y+10 →(ii)Let’s put Equation (i) in (ii),Here, 2y+10+y=70or, 3y+10=70or, 3y=70–10=60or, y= 60/30Therefore, y=20Now we’ll put y’s value in equation (i),Here, x=2*20+10or, x=40+10

Let’s think, 1st Number= x, 2nd Number=yAccording to question, x+y=70 → (i) ; x=2y+10 →(ii)Let’s put Equation (i) in (ii),Here, 2y+10+y=70or, 3y+10=70or, 3y=70–10=60or, y= 60/30Therefore, y=20Now we’ll put y’s value in equation (i),Here, x=2*20+10or, x=40+10Therefore, X=50

Let’s think, 1st Number= x, 2nd Number=yAccording to question, x+y=70 → (i) ; x=2y+10 →(ii)Let’s put Equation (i) in (ii),Here, 2y+10+y=70or, 3y+10=70or, 3y=70–10=60or, y= 60/30Therefore, y=20Now we’ll put y’s value in equation (i),Here, x=2*20+10or, x=40+10Therefore, X=50Recheck: x+y=70 ; 50+20=70

Let’s think, 1st Number= x, 2nd Number=yAccording to question, x+y=70 → (i) ; x=2y+10 →(ii)Let’s put Equation (i) in (ii),Here, 2y+10+y=70or, 3y+10=70or, 3y=70–10=60or, y= 60/30Therefore, y=20Now we’ll put y’s value in equation (i),Here, x=2*20+10or, x=40+10Therefore, X=50Recheck: x+y=70 ; 50+20=70Answer: x=50, y=20

Step-by-step explanation:

Here's mine, Hoping this helps you(Correct me if I'm wrong)..Have a great day!:)

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Answer 2

Answer:

The second number would be 108.

Step-by-step explanation:

Multiply 70 by 2 and subtract 32 from the product.