6 halves is 3.
B is at 3 1/2
3 1/2 minus 3 is 1/2
D would be plotted at 1/2.
Answer:Hope This Helps ☺️
Step-by-step explanation:
She is not correct because she did not substitute the same number in both expressions in Step 1
Step-by-step explanation:
CASE 1: substitute 1 for x to both sides of the equations
L.H.S
-(4x-5)+2(x-3)
-(4 (1) - 5)+ 2(1-3) = - (-1) + 2(-2) = 1 - 4 = -3
R.H.S
-2x - 5
-2(1) - 5 = -2-5 = -7
Hence for x= 1
-(4x-5)+2(x-3) ≠ -2x -5
Because -3 ≠ -7
CASE 2: substitute -1 for x to both sides of the equations
L.H.S
-(4x-5)+2(x-3)
-(4 (-1) - 5)+ 2(-1-3) = - (-9) + 2(-4) = 9 - 8 = 1
R.H.S
-2x - 5
-2(-1) - 5 = 2-5 = -3
Hence for x= -1
-(4x-5)+2(x-3) ≠ -2x -5
Because 1 ≠ -3
Answer:
She is not correct because she did not substitute the same number in both expressions in Step 1
Answer:
C, D
Step-by-step explanation:
This equation can be solved any of several ways. One that doesn't require much thought is using the quadratic formula.
For ax² +bx +c = 0, the solutions are ...
In the given equation, a=2, b=11, c=5, so this becomes ...
The solutions are ...
C. x = -5
D. x = -1/2
_____
My personal favorite is using a graphing calculator. The solutions are the x-intercepts of the expression on the left. That is, where its value is zero, as the equation says.
