Answer:
Step-by-step explanation:
ABCD is a parallelogram. AB is produced to P, such that AB = BP and PQ is drawn parallel to BC to meet AC produced at Q. Given AB = 8 cm, AD = 5 cm, AC = 10 cm.
→ BC ║ QP →→Given
In Δ ABC and ΔAPQ
∠ABC=∠APQ→→[BC ║ QP , BP is a transversal, so corresponding angles are equal]
∠BAC=∠PAQ→→Reflex angle
Δ ABC ~ ΔAPQ→→(AA similarity criterion]
When triangles are similar, their corresponding angles are equal.
AC=CQ=10 cm, shows that point C is mid point of AQ.
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