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2 years ago

Given: BCDF is a parallelogram; AB = BF Prove: angleA=angleE

Mathematics

1 answer:

Katen [24]2 years ago

7 0

Answer:

Step-by-step explanation:

ABCD is a parallelogram. AB is produced to P, such that AB = BP and PQ is drawn parallel to BC to meet AC produced at Q. Given AB = 8 cm, AD = 5 cm, AC = 10 cm.

→ BC ║ QP →→Given

In Δ ABC and ΔAPQ

∠ABC=∠APQ→→[BC ║ QP , BP is a transversal, so corresponding angles are equal]

∠BAC=∠PAQ→→Reflex angle

Δ ABC ~ ΔAPQ→→(AA similarity criterion]

When triangles are similar, their corresponding angles are equal.

AC=CQ=10 cm, shows that point C is mid point of AQ.

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$Area = \frac{3}{4} cm^2$

Step-by-step explanation:

Given

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Answer:

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Step-by-step explanation:

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dybincka [34]

Answer:

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Step-by-step explanation:

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2 years ago

A boundary stripe 6 in. wide is painted around a rectangle whose dimensions are 120 ft by 230 ft. Use differentials to approxima

Nimfa-mama [501]

Answer:

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Step-by-step explanation:

We are given that

Width of strip=6 in

Dimension of rectangle= $20 ft\times 230 ft$

We know that

Area of rectangle ,A=xy

Differentiate

$dA=\frac{\partial A}{\partial x}x+\frac{\partial A}{\partial y}y$

We have $\frac{\partial A}{\partial x}=y=230 ft$

$\frac{\partial A}{\partial y}=x=120$

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Because 6 in added in both side of breadth

dy= $\frac{12}{12}=1 ft$

Because 6 in added on both sides of length of rectangle

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3 years ago