Given: BCDF is a parallelogram; AB = BF Prove: angleA=angleE

Mathematics

1 answer:

Katen [24]2 years ago

7 0

Answer:

Step-by-step explanation:

ABCD is a parallelogram. AB is produced to P, such that AB = BP and PQ is drawn parallel to BC to meet AC produced at Q. Given AB = 8 cm, AD = 5 cm, AC = 10 cm.

→ BC ║ QP →→Given

In Δ ABC and ΔAPQ

∠ABC=∠APQ→→[BC ║ QP , BP is a transversal, so corresponding angles are equal]

∠BAC=∠PAQ→→Reflex angle

Δ ABC ~ ΔAPQ→→(AA similarity criterion]

When triangles are similar, their corresponding angles are equal.

AC=CQ=10 cm, shows that point C is mid point of AQ.

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