The minimum number of comparisons to find the smallest number from 5 integers is 4.
<h3>How to find the Smallest Integer?</h3>
Let the five numbers be a,b,c,d and e.
Let s be an integer
Comparison 1:
a and b will be compared first and the smaller number of them will be equal to s
Comparison 2:
Now, a smaller number between a and b that is s will be compared with c. Similarly, the smaller number of both numbers will be taken as s in the next comparison.
Comparison 3:
Likewise, s and d will be compared and a smaller number will be taken as s for the next comparison
Comparison 4:
Likewise, s and e will be compared and a smaller number will be taken as s for the next comparison.
After 4th comparison, s will be equal to smallest number of 5 integers.
Thus;
Total comparisons = 4
Therefore, the minimum number of comparisons to find the smallest number from 5 integers is 4.
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I think it would be the scholarly aptitude assessment
Answer:
opposite
Explanation:
Newton's 3rd law of motion: If object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.
so it should be opposite because the ground/floor pushes the shoe up and forward, the shoe pushes down and back.
correct me if you see a mistake.
Answer:
(15/17 = sin ∠ JLK)
(first option listed)
Explanation:
the "sin ∠ JLK" is what we can simply think of as the inside measurement of angle/corner L. (L is the letter in the middle of ∠ JLK , and if you imagine drawing a line from J to L to K, you would see that the only angle you formed both sides of is corner L)
so, we are looking for the sin of L.
(SOH CAH TOA)
we know that
sin = opposite / hypotenuse
However, we do not have the opposite value of this triangle <em>yet. </em>
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we can solve the length of the opposite side with the Pythagorean theorem:
a² + b² = c²
8² + b² = 17²
64 + b² = 289
- 64 - 64
b² = 225
√b² = √225
b = 15
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so, to solve for sin L,
(sin = opposite / hypotenuse)
we should divide the opposite (15) over the hypotenuse (17)
so, 15 / 17 = sin L
(15/17 = sin ∠ JLK)
