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7nadin3 [17]
2 years ago
9

It is manadatory to include a banner marking at the top of the page to alert the user that cui is present.

Computers and Technology
2 answers:
ololo11 [35]2 years ago
6 0
A. True is the right answer
prohojiy [21]2 years ago
3 0

Answer:

a I think

If correct mar brainliest

Explanation:

You might be interested in
Write a program that reads a file containing text. Read each line and send it to the output file, preceded by line numbers. If t
Shtirlitz [24]

Answer:

I am writing a JAVA program:

import java.io.FileReader;  // class used for reading data from a file

import java.io.IOException;  //class used for handling exceptions

import java.io.PrintWriter;  // class used to printing or writing formatted data. It is used when the data to be written contains text and numbers

import java.util.Scanner;   // class used to take input from the user

public class Main  {  //start of the class

public static void main(String[] args)  {//start of main() function body

Scanner input = new Scanner(System.in);  //creates Scanner class object

System.out.print("Enter the input file name: ");  // prompts user to enter the input file name

String input_file = input.next();  //to  read and return the token i.e. input file name and store this into input_file String type variable

System.out.print("Enter the output file name: "); // prompts user to enter the output file name

String output_file = input.next();   /to  read and return the token i.e. output file name and store this into output_file String type variable

try   {/* try  defines a chunk of code to be tested for errors during the execute of this chunk. its a code block for reading from input file and writing to output file. This handles the exception if program cannot create or write to the file indicated. */

   FileReader inFile = new FileReader(input_file);  //creates object inFile of FileReader class to read the input_file contents

   Scanner scan = new Scanner(inFile);  //read and scans the input file

   PrintWriter outFile = new PrintWriter(output_file);  //creates object outFile of PrintWriter class to write to the output file. It is used to write output data in a readable text form.

   int count = 1;    //counts the line number      

   while (scan.hasNextLine())  {  //loop keeps checking for the next line in input file

    String lines = scan.nextLine();  // reads the entire line of the input file and stores that line contents in String lines

    outFile.println("/* " + count + " */ " + lines);  //each line represented with line number enclosed in /* */

    count++;  }   //increments the line number at each iteration    

    outFile.close();        }  //closes the output file after writing the contents from input file with each line of the input file enclosed in  /* */

catch (IOException e)  {  // catching the IOException and prints the following message if program cannot create input_file or write to the output_file

   System.out.println("Error processing file: " + e);    }     }   }

Explanation:

The program is well explained in the comments mentioned with each statement of the above program. The user is prompted to enter input and output file names. Then the program uses a while loop that scans through lines of the input file and count variable counts each line of input file. Then at each iteration the count variable counts a line of input file and line number of each line of the input file is enclosed in /* */ delimiters. The contents of input file, in which the line numbers of text lines of the input file are enclosed in /* */ delimiters, is written to the output file.

The screenshot of the program is attached along with the output file produces as a result of this program execution.

7 0
3 years ago
Windows uses a memory-management technique known as ________ to monitor which applications you use most frequently and then prel
lukranit [14]

Answer:

SuperFetch

Explanation:

Superfetch is a memory management technique on windows service that enables or fetch frequently use applications on systems and launch them faster because the frequently use applications has been preload into the system memory for easy access when they want to be used.

SuperFetch always takes notice of all application running on your system in which when you exit a frequently used application SuperFetch will preload them immediately since it is saved on the system memory.

One of the most important part of Superfetch is that it saves alot of time because you don't have to search the applications before you get access to them in as far as the application was frequently used.

5 0
3 years ago
8.11 LAB: Count characters - functions Write a program whose input is a character and a string, and whose output indicates the n
Shkiper50 [21]

Answer:

#include<iostream>

using namespace std;

int CountCharacters(char userChar, const string inputstr){

   int k = 0;

   int iter = 0;

   for (iter = 0; iter < inputstr.size(); iter++){

       if (inputstr[iter] ==  userChar){

           ++k;        }}

   return k;}

int main(){

   string str;

   char userChar[1];

   cout<<"Char: ";    cin>>userChar;

   cin.ignore();

   cout<<"String: ";   getline(cin, str);

   cout<<CountCharacters(userChar[0],str);

   return 0;}

Explanation:

Written in C++:

The function is defined here:

int CountCharacters(char userChar, const string inputstr){

This initializes a count variable k to 0

   int k = 0;

This initializes an iterating variable iter to 0

   int iter = 0;

This iterates through the characters of the string being passed to the function

   for (iter = 0; iter < inputstr.size(); iter++){

This checks for matching characters

       if (inputstr[iter] ==  userChar){

If found,  k is incremented by 1

           ++k;        }}

This returns the total count

   return k;}

The main begins here

int main(){

This declares a string variable

   string str;

This declares a character variable

   char userChar[1];

This gets input for the character variable

   cout<<"Char: ";    cin>>userChar;

This lets the user get another input

   cin.ignore();

This gets input for the string variable

   cout<<"String: ";   getline(cin, str);

This calls the function and return the count of character in the string

   cout<<CountCharacters(userChar[0],str);

6 0
2 years ago
Each web site contains a(n) ____ page, which is the first document users see when they access the site.
katrin2010 [14]
Home is the answer. Hope this helps. :)
7 0
3 years ago
(a) Store last 7 digits of your student ID in a vector (7 element row or column vector). Write a MATLAB code which creates a 7x7
astra-53 [7]

Answer:

MATLAB code explained below with appropriate comments for better understanding

Explanation:

clc

clear all

ID = [1 2 3 4 5 6 7]; % Replace this with your student ID

%(a)

A = zeros(7);

for i=1:7

 

A(i,i)= ID(i);

 

end

fprintf('A =\n');

disp(A);

B = diag(ID);

fprintf('B =\n');

disp(B);

fprintf('Both A and B are same\n');

%(b)

if(mod(A(6,6),2)==0)

fprintf('A(6,6) is even\n');

else

fprintf('A(6,6) is odd\n');

end

%(c)

if(A(3,3)>0)

fprintf('A(3,3) is positive\n');

else if(A(3,3)<0)

fprintf('A(3,3) is negative\n');

else

fprintf('A(3,3)=0\n');

end

end

%(d)

fprintf('\nRequired series : ');

n = 35;

while n>=0

fprintf('%i',n);

if(n>0)

fprintf(', ');

end

n = n - 5;

end

fprintf('\n');

%(e)

n = input('\nInput an integer : ');

fprintf('%i! = ',n);

F = 1;

while n>1

F = F * n;

n = n - 1;

end

fprintf('%i\n',F);

%(f)

clear all

x = [3 7 2 1];

y = [4 3 9 1];

A = 0;

C = x(1);

for i=1:length(x)

A = A + x(i)*y(i);

B(i) = x(i)/y(i);

if(min(x(i),y(i))<C)

C = min(x(i),y(i));

end

end

C = 1/C;

fprintf('\nA = %i\n',A);

fprintf('B = ');

disp(B)

fprintf('C = %0.5g\n',C);

%(g)

clear all

A = randi([5 25],[1,10]);

maxA = A(1);

for i = 2:10

if(maxA<A(i))

maxA = A(i);

end

end

minA = A(1);

i = 2;

while i<11

if(minA>A(i))

minA = A(i);

end

i = i+1;

end

fprintf('\nA = ');

disp(A);

fprintf('maxA = %i\n',maxA);

fprintf('minA = %i\n',minA);

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%output

A =

1 0 0 0 0 0 0

0 2 0 0 0 0 0

0 0 3 0 0 0 0

0 0 0 4 0 0 0

0 0 0 0 5 0 0

0 0 0 0 0 6 0

0 0 0 0 0 0 7

B =

1 0 0 0 0 0 0

0 2 0 0 0 0 0

0 0 3 0 0 0 0

0 0 0 4 0 0 0

0 0 0 0 5 0 0

0 0 0 0 0 6 0

0 0 0 0 0 0 7

Both A and B are same

A(6,6) is even

A(3,3) is positive

Required series : 35, 30, 25, 20, 15, 10, 5, 0

Input an integer : 6

6! = 720

A = 52

B = 0.7500 2.3333 0.2222 1.0000

C = 1

A = 25 14 7 10 13 17 10 17 19 9

maxA = 25

minA = 7

>>

5 0
3 years ago
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