A. defragging your hard drive
Answer:
In C++:
int PrintInBinary(int num){
if (num == 0)
return 0;
else
return (num % 2 + 10 * PrintInBinary(num / 2));
}
Explanation:
This defines the PrintInBinary function
int PrintInBinary(int num){
This returns 0 is num is 0 or num has been reduced to 0
<em> if (num == 0) </em>
<em> return 0; </em>
If otherwise, see below for further explanation
<em> else
</em>
<em> return (num % 2 + 10 * PrintInBinary(num / 2));
</em>
}
----------------------------------------------------------------------------------------
num % 2 + 10 * PrintInBinary(num / 2)
The above can be split into:
num % 2 and + 10 * PrintInBinary(num / 2)
Assume num is 35.
num % 2 = 1
10 * PrintInBinary(num / 2) => 10 * PrintInBinary(17)
17 will be passed to the function (recursively).
This process will continue until num is 0
Answer:
Following are the solution to the given choices:
Explanation:
Given:
double currentBalance[91];//defining a double array
In point a:
The name of the array is= currentBalance.
In point b:
91 double values could be saved in the array. It requires 8bytes to hold a double that if the array size is 91*8 = 728
In point c:
Each element's data type is double.
In point d:
The array index range of values is between 0 and 90 (every array index starts from 0 and ends in N-1, here N=91).
In point e:
To access first element use currentBalance[0], for middle currentBalance[91/2] , for last currentBalance[90]
A. the modem provides the wifi or internet to the computer
