There are 12 more of white and blue cars than silver and red cars
Step-by-step explanation:
Step 1 :
Number of black cars counted by Ed = 23
Number of red cars counted by Ed = 9
Number of blue cars counted by Ed = 17
Number of white cars counted by Ed = 25
Number of silver cars counted by Ed = 21
We need to determine how many more white and blue cars are there than silver and red cars
Step 2 :
Total of white and blue cars = 25 + 17 = 42 cars
Total of sliver and red cars = 21 + 9 = 30 cars
Difference = 42 - 30 = 12 cars
Hence there are 12 more of white and blue cars than silver and red cars
Step 3 :
Answer :
There are 12 more of blue and white cars than red and silver cars
Answer:
x>9/5
Step-by-step explanation:
2/3x-1/5(+1/5)>1(+1/5)
[add 1/5 on both sides]
2/3x (÷3/2)>6/5 (÷3/2)
[flip 2/3 to 3/2 so that they cancel out]
x>9/5
Answer:
Step-by-step explanation:
a. HM = 14
HN = 21
HK = 10.5
Based on intersecting chords theorem,
HK*HJ = HM*HN
10.5*HJ = 14*21 (Substitution)
HJ = 294/10.5
HJ = 28
b. VC = 7.2
VG = 12
Based on tangent-secant theorem, thus:
VD*VC = VG²
VD*7.2 = 12²
VD = 144/7.2
VD = 20
Therefore,
CD = VD - VC
CD = 20 - 7.2
CD = 12.8
Answer:
1.07142857143
Step-by-step explanation:
Answer:
second option
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
Here diameter = 12, thus radius = 12 ÷ 2 = 6 and (h, k) = (2.5, - 3.5), thus
(x - 2.5)² + (y - (- 3.5))² = 6², that is
(x - 2.5)² + (y + 3.5)² = 36 ← equation of circle