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ArbitrLikvidat [17]
3 years ago
8

To make 2 batches of nut bars, Jayda needs to use 4 eggs. How many eggs are used in each batch of nuts? You have to find the uni

t rate.
Mathematics
2 answers:
Art [367]3 years ago
6 0
Since 4 eggs are used to make 2 batches. The unit rate would be 2 eggs per batch. So 2 batches/4 eggs= 1 batch/x eggs, the x would be 2 eggs.
goldenfox [79]3 years ago
3 0
2 for each batch.

Divide what is needed by what is in. In this case, she needs eggs, which are in nut bars.

4 / 2 = 2

2 eggs are in each nut bar.
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Which expression is equivalent to 3x5x5x5x5x5x5?
lana66690 [7]

Answer:

3*5^6

Step-by-step explanation:

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3 years ago
What is thesum of the two polynomials ? (-x^2+9)+(-3x^2-11x+4)
True [87]
-x^2 + 9 - 3x^2 - 11x + 4
-4x^2 - 11x + 13
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3 years ago
An ant looks up to the top of a tree at an angle of elevation of 40 degrees. If the ant is 30 feet from the base of the tree, wh
Alborosie
For the answer to the question above, this is a right triangle problem using the tangent function. 
<span>Tan(x) = Opposite (O) / Adjacent (A) </span>
<span>x = 40 degrees </span>
<span>A = 30 ft </span>
<span>Solve for O </span>
<span>O= Tan (x) * A </span>
<span>O = Tan (40) * 30 </span>
<span>Use your calculator or whatever method to get the tangent of 40 degrees (which is .84) </span>
<span>O = .84 * 30 </span>
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5 0
3 years ago
Read 2 more answers
Heeeeellllllpppppppp PLZ FAST
grin007 [14]
The answer to this question is b
6 0
3 years ago
A gambler has a coin which is either fair (equal probability heads or tails) or is biased with a probability of heads equal to 0
yawa3891 [41]

Answer:

(a) 0.1719

(b) 0.3504

Step-by-step explanation:

For every coin the number of heads follows a Binomial distribution and the probability that x of the 10 times are heads is equal to:

P(x)=\frac{n!}{x!(n-x)!}*p^x*(1-p)^{10-x}

Where n is 10 and p is the probability to get head. it means that p is equal to 0.5 for the fair coin and 0.3 for the biased coin

So, for the fair coin, the probability that the number of heads is less than 4 is:

P(x

Where, for example, P(0) and P(1) are calculated as:

P(0)=\frac{10!}{0!(10-0)!}*0.5^0*(1-0.5)^{10-0}=0.0009\\P(1)=\frac{10!}{1!(10-1)!}*0.5^1*(1-0.5)^{10-1}=0.0098

Then, P(x, so there is a probability of 0.1719 that you conclude that the coin is biased given that the coin is fair.

At the same way, for the biased coin, the probability that the number of heads is at least 4 is:

P(x\geq4 )=P(4)+P(5)+P(6)+...+P(10)

Where, for example, P(4) is calculated as:

P(4)=\frac{10!}{4!(10-4)!}*0.3^4*(1-0.3)^{10-4}=0.2001

Then, P(x\geq4 )=0.3504, so there is a probability of 0.3504 that you conclude that the coin is fair given that the coin is biased.

7 0
4 years ago
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