A sequence of numbers is formed by the iterative process 3/Un+1 U1 = 4 U2= U3=

A length of ribbon is cut into two pieces to use in a craft project. The graph shows the length of the second piece, x, for each

djyliett [7]

Answer:

Part A) The length of the ribbon is 15 feet

Part B) $m=-1$

Part C) see the explanation

Step-by-step explanation:

Part A)

Let

x -----> the length of the second piece of ribbon in feet

y -----> the length of the first piece of ribbon in feet

we know that

The length of the ribbon is equal to the sum of the first piece and the second piece of ribbon

so

y+x

take any point from the graph

Example

(13,2)

That means

Second piece ----> x=13 ft

First piece ----> y=2 ft

The length is (y+x)=2+13=15 ft

Part B) What is the slope of the line?

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

take the intercepts from the graph to calculate the slope

we have

(0,15) and (15,0)

substitute

$m=\frac{0-15}{15-0}$

$m=-1$

Part C) Explain what the slope of the line represents

we know that

The slope is equal to -1

That means, that we have a decreasing function, as the value of x (length of second piece) increases by one, the value of y (length of the first piece) decreases by one

The slope fits in the story because the linear equation in slope intercept form between the variable x and the variable y is equal to

$y=-x+15$

3 0

3 years ago

Plss answer fast it is so important

Levart [38]

4x^2 + 9y^2 + 12xy

hope this helps

7 0

3 years ago

16 PTS HAPPY HOLIDAYS

solong [7]

She is 12 feet above the ground.

3 0

4 years ago

SADFHUABSUDHAYSDXNINWYGBXIDNYW PLEASE ANSEWR

Alenkinab [10]

Answer:

$15x-6y=48$

Step-by-step explanation:

So we have the system of equations:

$5x-2y=16\\15x-7y=51$

And we want to multiply the first equation by some constant such that the resulting equation matches the coefficient of [x] in the second equation.

We can see that the coefficient of x in the second equation is 15.

So, to match 15, we must multiply the first equation by 3. So:

$3(5x-2y)=3(16)$

Multiply:

$15x-6y=48$

And we're done!

5 0

3 years ago

Read 2 more answers

The scores on the GMAT entrance exam at an MBA program in the Central Valley of California are normally distributed with a mean

Kaylis [27]

Answer:

58.32% probability that a randomly selected application will report a GMAT score of less than 600

93.51% probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600

98.38% probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

$\mu = 591, \sigma = 42$

What is the probability that a randomly selected application will report a GMAT score of less than 600?

This is the pvalue of Z when X = 600. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{600 - 591}{42}$

$Z = 0.21$

$Z = 0.21$ has a pvalue of 0.5832

58.32% probability that a randomly selected application will report a GMAT score of less than 600

What is the probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600?

Now we have $n = 50, s = \frac{42}{\sqrt{50}} = 5.94$

This is the pvalue of Z when X = 600. So

$Z = \frac{X - \mu}{s}$

$Z = \frac{600 - 591}{5.94}$

$Z = 1.515$

$Z = 1.515$ has a pvalue of 0.9351

93.51% probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600

What is the probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600?

Now we have $n = 50, s = \frac{42}{\sqrt{100}} = 4.2$

$Z = \frac{X - \mu}{s}$

$Z = \frac{600 - 591}{4.2}$

$Z = 2.14$

$Z = 2.14$ has a pvalue of 0.9838

98.38% probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600

8 0

3 years ago