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vodomira [7]
2 years ago
7

A pressure of a gas at 22°C is 600 mmHg when it occupies 2.5 L. If the gas is compressed to 1.8 L and the pressure changes to 76

0 mmHg. What is the new temperature in Kelvin?​
Mathematics
1 answer:
zhuklara [117]2 years ago
6 0

APPLICATION OF COMBINED GAS LAW

Combined gas law is a combination of Boyle's, Charles', and Gay-Lussac's Laws that expresses the relationship between pressure, temperature, and volume in a constant amount of gas (moles).

<u>Note:</u>

  • In solving any problems related to Gas Law, it is important to remember that the standard unit measure for the temperature is always expressed in Kelvin (K). To do so, whatever the given temperature is (either °C or °F) you should convert them first so computation will be efficient.
  • If the given is in °C, then use the formula \sf{K = °C + 273.15}
  • And if °F, \sf K =  \frac{5}{9} (°F - 32) + 273.15

So to answer your question, what is the new temperature in K, the new temperature is T2 = 269.176 K or 269.18 K

(Please see attached image for the solution).

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Jane earns a 5.5% commission on the selling price of each home she sells. She earned $9,020 in commission on the sale of a home.
ratelena [41]

Answer:

"$164000" is the appropriate answer.

Step-by-step explanation:

Let the selling price be "s".

As per the question,

If Jane take 5.5% of selling price i.e.,

= 0.055\times s

Given commission,

= $9,020

then,

The selling price will be:

⇒ 0.055\times s=9020

                s=\frac{9020}{0.055}

                   =164000 ($)    

6 0
2 years ago
Find the center and radius of the circle whose equation is x 2 + y 2 + 10x − 1
Margaret [11]

we conclude that the center of the circle is the point (-5, 0).

<h3>How to find the center of the circle equation?</h3>

The equation of a circle with a center (a, b) and a radius R is given by:

(x - a)^2 + (y - b)^2 = R^2

Here we are given the equation:

x^2 + y^2 + 10x - 1 = 0

Completing squares, we get:

x^2 + 10x + y^2 = 1

Now we can add and subtract 25 to get:

x^2 + 10x + 25 - 25 + y^2 = 1\\\\(x + 5)^2 -25 + y^2 = 1\\\\(x + 5)^2 + (y - 0)^2 = 26

Comparing that with the general circle equation, we conclude that the center of the circle is the point (-5, 0).

If you want to learn more about circles:

brainly.com/question/1559324

#SPJ1

3 0
2 years ago
True or false? A correct answer is worth (2 pts). Explain how you know for the additional (2 pts). Using complete sentence for (
PtichkaEL [24]

<u>answer (in words)</u>

FALSE. the coordinate pair (5, 2) is not a solution to the equation 2x+3y=10. in order to figure out whether or not the statement is true or false, plug the x and y values from the coordinate pair (5, 2) into the given equation, 2x+3y=10. if both sides of the equation end up equal, the coordinate pair is a solution to the equation. if not, the coordinate pair is not a solution to that equation.

<em>(i hope i explained that well enough, i'm better at explaining it algebraically as opposed to putting it into words lol)</em>

<u>answer (algebraic/steps for solving)</u>

first, plug in 5 for x in the equation 2x+3y=10.

  • 2x+3y=10 ⇒ 2(5)+3y=10

then plug in 2 for y.

  • 2(5)+3y=10 ⇒ 2(5)+3(2)=10

now your equation is 2(5)+3(2)=10. all that's left to do is to simplify. you can do this in whatever order you'd like, but i'll start with multiplying 2 · 5.

  • 2(5)+3(2)=10 ⇒ 10 + 3(2) = 10

multiply 3 · 2.

  • 10 + 3(2) = 10 ⇒ 10 + 6 = 10

add 10 + 6.

  • 10 + 6 = 10 ⇒ 16=10

16 and 10 are <em>not</em> equal, therefore (5, 2) is not a solution to the equation 2x+3y=10. in order for a coordinate pair to be the solution to an equation, both sides of the equation need to end up equal after solving and simplifying.

i hope this helps! have a great rest of your day <3

6 0
3 years ago
Can someone be honest and tell me if it’s correct bc I’m not sure someone please help me
patriot [66]
Yes it is........
......
5 0
3 years ago
(2y-1)(4y-3) What is the answer to this?
Likurg_2 [28]
(2y-1)(4y-3)=2y\cdot4y+2y\cdot(-3)-1\cdot4y-1\cdot(-3)\\\\=8y^2-6y-4y+3=8y^2-10y+3
4 0
3 years ago
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