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raketka [301]
3 years ago
11

Write an equivalent expression for 27x+18

Mathematics
2 answers:
Lynna [10]3 years ago
8 0
9(3x+2) hope this helps
EleoNora [17]3 years ago
5 0
3(9x+6)
You do, 3·9x=27x
3·6=18
27x+18
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Which decimal is equivalent to 13/11
TiliK225 [7]

Answer:

1.18 is the answer but if u want to round u have the answer as 1.20=1.2

7 0
3 years ago
Read 2 more answers
F(x)=x+3 , G(x)=x^2-2<br> (F/G)(-1)-G(3)
trapecia [35]

f(x)=x+3;\ g(x)=x^2-2\\\\\left(\dfrac{f}{g}\right)(-1)-g(3)=?\\\\\left(\dfrac{f}{g}\right)(x)=\dfrac{f(x)}{g(x)}\\\\g(3)=3^2-2=9-2=7\\\\f(-1)=-1+3=2\\\\g(-1)=(-1)^2-2=1-2=-1\\\\\left(\dfrac{f}{g}\right)(-1)-g(3)=\dfrac{2}{-1}-7=-2-7=-9

7 0
3 years ago
Can somebody help me with this? Thank you
melomori [17]

Answer:

x≥1 or x≤−3

Step-by-step explanation:

x+1≥2  possibility 1

x+1−1≥2−1  Subtract 1 from both sides

x≥1

x+1≤−2  Possibility 2

x+1−1≤−2−1  Subtract 1 from both sides

x≤−3

4 0
3 years ago
Clara has a lawn in front of her house as mapped on the coordinate plane. She wants to plant a bed of flowers between the points
Hunter-Best [27]

Answer:

<em>Look Below In the Explanation</em>

Step-by-step explanation:

Point P has coordinates of (4,4) and point Q has coordinates of (4,-4).

Since both points have the same x-coordinates we can subtract point Q's y-coordinate from point P's y-coordinate.

I will set the equation up and try and figure this part by yourself. I hope you learned what to do from previous questions that are very similar to this that I answered.

4 - ( -4) = length of the bed of flowers

Hope that helps and maybe earns a brainliest!

Have a splendid day! :^)

3 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%7B%7D%5E%7B2%7D%20-%204%20%7D%7B%20%5Csqrt%7Bx%20%7B%7D%5E%7B2%7D%20-%206x%2
Nimfa-mama [501]

First of all, we can observe that

x^2-6x+9 = (x-3)^2

So the expression becomes

\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}

This means that the expression is defined for every x\neq 3

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2

Since we can't accept 3 as an answer, the actual solution set is

(-\infty,-2] \cup [2,3) \cup (3,\infty)

7 0
3 years ago
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