Answer:
X from 0 to 21
Y from 0 to 7
Z from 0 to 3
Step-by-step explanation:
Since we are being asked by the integration limits in first octant (positive x, positive y and positive z) we need to know where does the plane intersect this axes. For this we have:
for x=0 and y=0
7z=21
z=3
for x=0 and z=0
3y=21
y=7
for z=0 and y=0
x=21
This means that the integration limits are:
4 bags
lxw
12x10=120
30x4=120
l=length
w=width
1. (-20/3)+[(2×3+2)/3]=-12/3=4
2. (-5/3)-(2/3)-3= -5-2-6=-3
