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dusya [7]
3 years ago
7

Find the limits of integration ly, uy, lx, ux, lz, uz (some of which will involve variables x,y,z) so that ∫uz lz∫uxlx∫uyly????y

????x????z represents the volume of the region in the first octant that is bounded by the 3 coordinate planes and the plane x+3y+7z=21.
Mathematics
1 answer:
SSSSS [86.1K]3 years ago
8 0

Answer:

X from 0 to 21

Y from 0 to 7

Z from 0 to 3

Step-by-step explanation:

Since we are being asked by the integration limits in first octant (positive x, positive y and positive z) we need to know where does the plane intersect this axes. For this we have:

for x=0 and y=0

7z=21

z=3

for x=0 and z=0

3y=21

y=7

for z=0 and y=0

x=21

This means that the integration limits are:

X from 0 to 21

Y from 0 to 7

Z from 0 to 3

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Step-by-step explanation:

First day:

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After first day, 20% 0f 50,000 are removed.

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Contestants remaining after first day = 50,000-10,000 = 40,000

Second day:

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Balance =40000-8000=32,000

Third day:

Contestants= 32000

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Fouth day:

Contestants= 25,600

20% removed

That is (20/100)×25,600=5,120

Balance =25,600-5,120=20,480

Fifth day:

Contestants= 20,480

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That is (20/100)×20,480=4096

Balance =20,480-4096=16,384

Sixth day:

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That is (20/100)×16,384=3276.8

Balance =16,384-3276.8=13,107.2

Seventh day:

Contestants= 13,107.2

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That is (20/100)×13,107.2=2621.44

Balance =13107.2-2621.44=10485.76

Therefore, number of contestants remaining after one week equals 10,486.

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