What is the range for these two problems and what did I miss for the graphs? please show me the correct answer.

Mathematics

2 answers:

zalisa [80]3 years ago

8 0

Problem 3, part 1

The graph is shown below. Refer to figure 1. It looks like you have the right idea, but the left-most piece of the graph is incorrect. Take note how the left-most piece is going uphill when moving left to right. This is due to the positive slope for y = 2x+5.

The graph shows that nearly the entire real number line is covered when it comes to the range; however, there's a gap from y = 4 to y = 6. We're not including y = 4 in the range, but we include y = 6 in the range.

The lower part of the range spans from negative infinity up to y = 4, excluding that endpoint. So we have $(-\infty, 4)$ as part of the range.

The upper half of the range is from y = 6 onward to infinity. We include y = 6. This means $[6, \infty)$ is also part of the range.

<h3>Answer: The range in interval notation is $(-\infty, 4) \ \cup \ [6, \infty)$ </h3>

The square bracket says to include 6 as part of the range. The "U" symbol is the union operation to glue together the two disjoint intervals.

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Problem 3, part 2

Move onto figure 2 for the graph. It appears you didn't graph the V shape correctly for the absolute value piece of y = 2|x+6|. That's the red portion of the graph in figure 2. As the graph shows, we can target any nonnegative y value. Therefore y = 0 or larger. In terms of an inequality, we would say the range is $y \ge 0$