Answer:
Step-by-step explanation:
<u><em>The picture of the question in the attached figure</em></u>
we know that
The measure of the external angle is the semi-difference of the arches it covers.
so
![m\angle GET=\frac{1}{2}[arc\ TN-arc\ TG]](https://tex.z-dn.net/?f=m%5Cangle%20GET%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20TN-arc%5C%20TG%5D)
Remember that the diameter divide the circle into two equal parts
In this problem
TN is a diameter
we have
----> because is half the circle (TN is a diameter)
---> is given
substitute
![m\angle GET=\frac{1}{2}[180^o-46^o]=67^o](https://tex.z-dn.net/?f=m%5Cangle%20GET%3D%5Cfrac%7B1%7D%7B2%7D%5B180%5Eo-46%5Eo%5D%3D67%5Eo)
Answer:
33 yrs old
Step-by-step explanation:count up to the year he was born
The way you'd set it up would be sin55º/12=sinB/14 (you could also flip the equation so that 12/sin55º=14/sinB, you'll get the same answer either way). Multiply out so that its 14•sin55º=12•sinB, or 11.47=12•sinB. Divide both sides by 12 so that it looks like .96=sinB, then take arcsine of both sides (arcsin= x=sin^-1 theta+360n or x=180- (sin^-1 theta)+360n), which should give you about 72.88º and 107.12º.
Answer: No
Step-by-step explanation:
First add the 48.75 and 18.30 together.
second multiply 5.50 by 9
she would only earn 49.50 so she won’t be able to buy the bike and helmet
Answer:
Step-by-step explanation:
divide each by x
