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grin007 [14]
3 years ago
14

alfredo bought a fishing pole for 60 off it's original price of $97 if the tax was 4% how much did alfredo pay for the fishing p

ole
Mathematics
1 answer:
Agata [3.3K]3 years ago
3 0

Answer:

$40.4

Step-by-step explanation:

The regular price of the fishing rod is $97

There is a 60% discount from that price.

The discount is equal to 60% of $97 which is equal to .60 * $97 which is equal to $58.2

Discount is like a markdown, so subtract $58.2 from the price of the item before the change to get $97 - $58.2 = $38.8 

This is the price of the item before tax is applied.

Now you apply the sales tax of 4%.

4% of $38.8 is equal to .04 * $38.8 which is equal to $1.552

Tax is like a markup, so add $1.552 to the price of the item before tax was applied to get a selling price of $38.8 + $1.552 which is equal to $40.352

Round it up and the answer is $40.4

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zubka84 [21]
So, standard form basically takes the shape of Ax+By=C. You want all of your variables to be on the left side and your constant on the right. There can also be no fractions!

In your case, since you didn't mention a y value for y, your line is y=-3/2x+6

first we get rid of the fraction by multiplying both sides of the equation by 2:
(2)y= (-3/2x+6)(2) and get
2y=-3x+12
now all there is left to do is get x to the other side by adding it to both sides:
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3 years ago
9/24 Yall already know im stuck again will mark brainlyest
svp [43]

Answer:

Step-by-step explanation:

1. -35, 2

2. -72, -6

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4. 40, 13

5. -15, 2

6. -30, 7

7. 30, 11

8. 42, -13

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10. -4, 20

11. 7, 1

12. 4, -24

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16. 9, 3

17. -10, 11

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19. 11, 6

20. 1, -9

21. -9, 4

22. -8, 7

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7 0
3 years ago
Which number is greater tha 9/4​
Naddika [18.5K]

Answer:

9

Step-by-step explanation:

the biggest number gets eaten by the alligator

5 0
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Solve for x. −1.5x = −2.55 A) −1.5 B) 1.5 C) 1.7 D) 1.9
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Answer:

C

Step-by-step explanation:

-1.5x=-2.55

1.5x=2.55

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3 years ago
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faust18 [17]

x^3 is strictly increasing on [0, 5], so

\max\{x^3 \mid 0\le x\le5\} = 5^3 = 125

and

\min\{x^3 \mid 0 \le x\le5\} = 0^3 = 0

so the integral is bounded between

\displaystyle \boxed{0} \le \int_0^5x^3\,dx \le \boxed{125}

8 0
2 years ago
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