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2 years ago

2) State the area of the given triangle.

Mathematics

2 answers:

ser-zykov [4K]2 years ago

8 0

Answer:

the answer is b

Step-by-step explanation:

took on k12

sammy [17]2 years ago

5 0

Answer:

i'm pretty sure its 36 aka b

Step-by-step explanation:

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Sean collects trading cards. The number of cards that he owns is given by the fiction y=10x+25, where is x is the time of months

Nuetrik [128]

The best is A ,,
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However, B is also right option...

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3 years ago

Find the surface area

Brut [27]

Answer:

Step-by-step explanation:

area of top=7×6=42 yd²

area of bottom=3×6=18 yd²

area of two rectangles=2[4×6]=48 yd²

area of two trapezoids=2[1/2(7+3)×3.5]=35 yd²

total surface area=42+18+48+35=143 yd²

7 0

3 years ago

Solve i=Prt for t, if i=105,p=700,and r=0.05

Katen [24]

3675. You multiply 105 700, then you multiply the answer by 0.05.

5 0

3 years ago

Read 2 more answers

Miles sells 3 raffle tickets for $18 and 4 tickets for $24. The pattern for the price of the tickets is the same. How much money

serg [7]

Answer:

If Miles sells 6 tickets the money he will collect be $36.

Step-by-step explanation:

Given:

Miles sells 3 raffle tickets for $18 and 4 tickets for $24.

The pattern for the price of the tickets is the same.

Now, to find the money miles will collect if he sells 6 tickets.

Let the money Miles will collect be $x.$

The ticket if sells will be 6.

As, Miles sells 3 tickets for $18.

And the pattern for the price is same.

So, 3 is equivalent to 18.

And, 6 is equivalent to $x.$

Now, to get the money by using cross multiplication method:

$\frac{3}{18} =\frac{6}{x}$

By cross multiplying we get"

$3x=108$

Dividing both sides by 3 we get:

$x=36.$

The money MIles will collect = $36.

Therefore, if Miles sells 6 tickets the money he will collect is $36.

5 0

3 years ago

If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.

Lelechka [254]

Answer:

$\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }$

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

$f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)$

So we can say that

$a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}$

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

$(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab$

and we can notice that

$a^2+b^2=(a+b)^2-2ab$ so

$(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab$

it comes

$x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}$

multiply by 3

$3x^2-20x+2*16+5=3x^2-20x+37$

4 0

3 years ago