Using the condition given to build an inequality, it is found that the maximum number of junior high school student he can still recruit is of 17.
<h3>Inequality:</h3>
Considering s the number of senior students and j the number of junior students, and that he cannot recruit more than 50 people, the inequality that models the number of students he can still recruit is:
In this problem:
- Already recruited 28 senior high students, hence
.
- Already recruited 5 junior high students, want to recruit more, hence
.
Then:
The maximum number of junior high school student he can still recruit is of 17.
You can learn more about inequalities at brainly.com/question/25953350
We want to subtract 8x + 3 from -2x+5. We can create an expression to represent this.
-2x + 5 - (8x + 3).
After this, lets distribute the - sign (think of this like expanding something with -1).
-2x + 5 - 8x - 3
Lastly, we just need to combine like terms.
-2x + 5 - 8x - 3
Combine the 5 and -3 to get 2.
-2x + 2 - 8x
Combine the -2x and -8x to get -10x.
-10x + 2
The final answer to the question is therefore A.
The objective is to state why the value of
converging alternating seies with terms that are non increasing in magnitude
lie between any two consecutive terms of partial sums.
Let alternating series
<span>Sn = partial sum of the series up to n terms</span>
{S2k} = sequence of partial sum of even terms
{S2k+1} = sequence of partial sum of odd terms
As the magnitude of the terms in the
alternating series are non-increasing in magnitude, sequence {S2k} is bounded
above by S1 and sequence {S2k+1} is bounded by S2. So, l lies between S1 and
S2.
In the similar war, if first two terms of the
series are deleted, then l lies in between S3 and S4 and so on.
Hence, the value of converging alternating
series with terms that are non-increasing in magnitude lies between any two
consecutive terms of partial sums. So, the remainder Rn = S – Sn alternating
sign
<span> </span>
The total amount of interest will be found using compound interest formula:
A=p(1-r/100)^n
A=future amount
p=principle
r=rate
n=time
From the information given:
p=$6500, r=6%, n=25 years
thus
A=6500(1+6/100)^25
A=6500(1.06)^25
A=$27,897.16
Answer: 27897.12-6500=$$21397.2
Answer:
So you say you want some 5 digit numbers eh? Let’s consider some boundaries. 5 digit numbers range from 10,000 - 99,999. So our number is guaranteed to be between 0 and 90000.
Sometimes it’s much easier to work with concrete things. Such as the number of numbers that don’t contain any 3s. It’s really more difficult to put our finger on “at least 1” anything so we try to steer clear of it.
Anyways we’ve got 90000 numbers that have at least 1 or 0 3’s. Find one and we know the other.
So no 3’s at all right? Well you have 8 choices for the first digit (can’t choose 0 and you can’t choose 3). And then for the remaining 4 digits you have 9 choices. So that’s
8∗94=52488
Back to our initial equation, we have
90000−8∗94=37512 5 digits numbers without any 3s.
A quick (or maybe not so quick) matlab script confirms such calculations.
credits to : Trevor Squires
