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igor_vitrenko [27]
3 years ago
11

Write the equation of the line passing through (-3,4) and perpendicular to -2x+7y=-3.​

Mathematics
1 answer:
mario62 [17]3 years ago
4 0
your answer would be y= -2/7x + 4
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Make -2/3 as a whole number PLZ
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You can make a fraction a whole number by multiplying the fraction by the same number in the denominater. So if you multiply -2/3 by 3, so your answer would be -2
Hope this helps :)
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Solve the system of equations and choose the correct ordered pair.
nasty-shy [4]
The answer is D

Because if you replace the variables just by testing them they give the answer as X=-3 and Y=3.
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so they comply with the required to be the correct answer, even though you can make a system of equation.  


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Determine whether the graph of the equation is symmetric with respect to the y-axis, the x-axis, the origin, more than one of th
Murrr4er [49]
\bf x^2y^2+3xy=1\\\\
-------------------------------\\\\
\stackrel{\stackrel{\textit{test for x-symmetry}}{y=-y}}{x^2(-y)^2+3x(-y)=1}\implies x^2y^2-3xy=1\impliedby 
\begin{array}{llll}
\textit{function differs}\\
\textit{from original}\\
\textit{no dice}
\end{array}\\\\
-------------------------------\\\\

\bf \stackrel{\stackrel{\textit{test for y-symmetry}}{x=-x}}{(-x)^2y^2+3(-x)y=1}\implies x^2y^2-3xy=1\impliedby 
\begin{array}{llll}
\textit{function differs}\\
\textit{from original}\\
\textit{no dice}
\end{array}\\\\
-------------------------------\\\\
\stackrel{\stackrel{\textit{test for origin-symmetry}}{x=-x~~y=-y}}{(-x)^2(-y)^2+3(-x)(-y)=1}\implies x^2y^2+3xy=1\impliedby 
\begin{array}{llll}
origin\\symmetry
\end{array}

so, recall, the function has symmetry when the yielded resulting function resembles the original function, after negativizing the variable(s).

Also recall that minus*plus is minus, and minus*minus is plus.
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4 years ago
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artcher [175]
False explanation..........
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3 years ago
Find the unit rate. 16 miles in 4 hours
MatroZZZ [7]

Answer:

4 miles per hour

Step-by-step explanation:

divide 16 by 4

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