What is the area of a rectangle whose width is 6y units and whose length is 4y+2x-6 units?

Mathematics

1 answer:

ValentinkaMS [17]2 years ago

6 0

Answer:

66473737

Step-by-step explanation:

747292929277273664646272727282891919919191919919192929298475756565665

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irinina [24]

The probability of drawing a two and another 2 is 1/72

<h3>What is probability?</h3>

Probability is the likelihood or chance that an event will occur

Since the total number in the board game is 9, hence the probability of drawing a 2 will be 1/9

The probability of drawing the second 2 will be 1/8

Pr(drawing a 2, then drawing another 2) = 1/9 * 1/8

Pr(drawing a 2, then drawing another 2) = 1/72

Hence the probability of drawing a two and another 2 is 1/72

learn more on probability here: brainly.com/question/24756209

4 0

2 years ago

Factorise x^2/4-y^2/4

Nuetrik [128]

Answer:

$\large\boxed{\left(\dfrac{x}{2}-\dfrac{y}{2}\right)\left(\dfrac{x}{2}+\dfrac{y}{2}\right)=\dfrac{x-y}{2}\cdot\dfrac{x+y}{2}}$

Step-by-step explanation:

$\dfrac{x^2}{4}-\dfrac{y^2}{4}=\dfrac{x^2}{2^2}-\dfrac{y^2}{2^2}\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\=\left(\dfrac{x}{2}\right)^2-\left(\dfrac{y}{2}\right)^2\qquad\text{use}\ (a-b)(a+b)=a^2-b^2\\\\=\left(\dfrac{x}{2}-\dfrac{y}{2}\right)\left(\dfrac{x}{2}+\dfrac{y}{2}\right)=\dfrac{x-y}{2}\cdot\dfrac{x+y}{2}$