Evaluate the expression 1 2 over 5 x plus 3 2 over 3 for x equals 1 fourth.
1 answer:
<em>The </em><em>evaluated expression </em><em>needed is </em> <em>or </em>3
The expression that needs to be evaluated is
1 + 3
for x =
We are being asked here to solve the mathematical equation by substituting the value of x for 1/4. If we go ahead and do the substitution we have;
1 + 3
where x = = 0.25
this is equal to
1 + 3
=
1 * 8/5 + 3 * 2/3
8/5 + 2 = 18/5 = 3
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Given -:
EF = 2X-7
FG = 4X-20
EG = 21
FIND OUT
EF =?
FG = ?
To proof
as given in the question
we have the value of EF = 2X-7 , FG = 4X-20 and EG = 21
Thus we have
EG = EF + FG
21 = 2X-7 + 4X- 20
21 = 6x - 27
48 = 6x
x = 8
Hence proved
Now put this value
Now
Hence proved
Answer:
A 180° rotation of then a dilation by a scale factor of one-third
Step-by-step explanation:
The coordinates of the vertices of ΔABC are;
A(-9, 3), B(-9, 6), and C(0, 3)
The coordinates of the vertices of ΔA'B'C' are;
A'(3, -1), B'(3, -2), and C'(0, -1)
We note that for a 180° rotation transformation about the origin, we get;
Coordinates of preimage = (x, y)
Coordinates of image after 180° rotation about the origin = (-x, -y)
Therefore, a 180° rotation of ΔABC about the origin, would give ΔA''B''C'' as follows;
A(-9, 3), B(-9, 6), and C(0, 3) = A''(9, -3), B''(9, -6), and C''(0, -3)
The formula for a dilation of a point about the origin is given as follows;
Where;
k =The scale factor = 1/3, (one-third) we have;
A dilation of ΔA''B''C'', by a scale factor of 1/3, we get ΔA'B'C' as follows;
The coordinates of the vertices of ΔA'B'C' are A'(3, -1), B'(3, -2), and C'(0, -1), which is the same as the required coordinates of the image;
Therefore, the transformation that can be performed to show that ΔABC and ΔA'B'C' are similar are rotating ΔABC by 180° then a dilating the image derived after rotation by a scale factor of one-third (1/3) we get ΔA'B'C'.