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3 years ago

14

For a convex 41-gon, what is the sum of the measures of the interior angles?

1 answer:

Sonja [21]3 years ago

7 0

Given:

convex 41-gon
n = 41

Required:

Sum of interior angles.

Solution:

To solve for the sum of interior angles, we can use the formula:

Sum of interior angles = 180(n-2)°

Substituting,

Sum of interior angles = 180(41-2)°

Sum of interior angles = 7020°

Therefore, the sum of the measures of the interior angle of a convex 41-gon is 7020°.

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