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Alik [6]
2 years ago
9

Plz help with this question.

Mathematics
2 answers:
Galina-37 [17]2 years ago
7 0

Answer:

Both \:  the \:  moon  \: and  \: earth  \: are  \: in \:  \\  the  \: shape \:  of  \: spheres. \\ Surface\: area  \: of \:  a \: sphere  \: of  \: radius \:  'r' \\

Let d1 be the diameter of the moon and d2 and be the diameter of the earth.Let r1 be the radius of the moon and r2 be the radius of the earth.

given \: d1 =  \frac{1}{4}d2 \\ = > 2r1 =  \frac{1}{4} ×2r2  \\  =>r1 =  \frac{1}{4}×r2 \\ Now,  \: ratio \:  of \:  \:  their  \: surface \:  areas \:  is:  \\ =  s1: s2 \\  = r {1}^{2}: r {2}^{2} \\ = {1}^{2 } : {4}^{2 } \\ =1:16

<h2> hope it helps you</h2>
cricket20 [7]2 years ago
6 0

Answer:

look below :)

Step-by-step explanation:

Ok so the formula for the area of a triangle is (l x w) / 2

and the formula for the area of a square is l x w.

The area of the square is 2 x 2 = 4.

so the area of the square = 4cm²

the area of the triangle is 2 x 4 = 8.

8 / 2 = 4

so the area of the triangle is also 4cm².

Hope this helped!

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The radius of the wheel on a bike is 21 inches. If the wheel is revolving at 154 revolutions per minute, what is the linear spee
Bezzdna [24]

Answer:

The linear speed of the bike is 19.242 miles per hour.

Step-by-step explanation:

If sliding between the bottom of the wheel and ground can be neglected, the motion of the wheel can be well described by rolling, which is a superposition of coplanar pure rotation and translation, The speed of the bike occurs at the center of the wheel, where resulting instantaneous motion is pure translation parallel to ground orientation. The magnitude of the speed of bike (v_{B}), measured in inches per second, is:

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Where:

R - Radius, measured in inches.

\omega - Angular speed, measured in radians per second.

Now, the angular speed must be converted from revolutions per minute into radians per second:

\omega = \left(154\,\frac{rev}{min} \right)\cdot \left(2\pi\,\frac{rad}{rev} \right)\cdot \left(\frac{1}{60}\,\frac{min}{s}  \right)

\omega \approx 16.127\,\frac{rad}{s}

The speed of the bike is: (R = 21\,in and \omega \approx 16.127\,\frac{rad}{s})

v_{B} = (21\,in)\cdot \left(16.127\,\frac{rad}{s} \right)

v_{B} = 338.667\,\frac{in}{s}

Lastly, the outcome is converted into miles per hour:

v_{B} = (338.667\,\frac{in}{s} )\cdot \left(3600\,\frac{s}{h} \right)\cdot \left(\frac{1}{63360}\,\frac{mi}{in}  \right)

v_{B} = 19.242\,\frac{mi}{h}

The linear speed of the bike is 19.242 miles per hour.

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