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3 years ago

Angle 1 = 27° find the measure of angle 4

Mathematics

1 answer:

Vesna [10]3 years ago

3 0

Answer:

27°

because angle 1=27° so 2=27°

4=2 so 4=27° as well

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3 years ago

A German Shepard puppy weighs 9 pounds and is gaining 5 pounds each month. A Great Dane puppy weighs 11 pounds and is gaining 4

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2 months

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4 years ago

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A second important result is that electrons will fill the lowest energy states available. This would seem to indicate that every

Assoli18 [71]

Answer:

Explanation:

1) Principal quantum number, n = 2

n is the principal quantum number and indicates the main energy level.

2) Second quantum number, ℓ

The second quantum number, ℓ, is named, Azimuthal quantum number.

The possible values of ℓ are from 0 to n - 1.

Hence, since n = 2, there are two possible values for ℓ: 0, and 1.

This gives you two shapes for the orbitals: 0 corresponds to "s" orbitals, and 1 corresponds to "p" orbitals.

3) Third quantum number, mℓ

The third quantum number, mℓ, is named magnetic quantum number.

The possible values for mℓ are from - ℓ to + ℓ.

Hence, the poosible values for mℓ when n = 2 are:

for ℓ = 0: mℓ = 0

for ℓ = 1, mℓ = -1, 0, or +1.

4) Fourth quantum number, ms.

This is the spin number and it can be either +1/2 or -1/2.

Therfore the full set of possible states (different quantum number for a given atom) for n = 2 is:

(2, 0, 0 +1/2)
(2, 0, 0, -1/2)
(2, 1, - 1, + 1/2)
(2, 1, -1, -1/2)
(2, 1, 0, +1/2)
(2, 1, 0, -1/2)
(2, 1, 1, +1/2)
(2, 1, 1, -1/2)

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8 0

3 years ago

Please solve this, will rate 5 stars and mark as STAR!

Nina [5.8K]

Answer:

$\boxed{5 \cdot \sqrt{2} \cdot \sqrt[6]{5} }$

Step-by-step explanation:

$\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }$

$\sqrt{\sqrt[3]{10} } \implies (10^\frac{1}{3} )^\frac{1}{2} =10^\frac{1}{6} =\sqrt[6]{10}$

$\therefore \sqrt{\sqrt[3]{10} }=\sqrt[6]{10}$

$\text{Solving }\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }$

$250=2 \cdot 5^3$

$\sqrt[3]{250}=\sqrt[3]{2\cdot 5^3}=5 \sqrt[3]{2}$

Once

$\sqrt[6]{2} \cdot \sqrt[6]{5} = \sqrt[6]{10}$

We have

$5 \sqrt[3]{2} \cdot \sqrt[6]{2} \cdot \sqrt[6]{5}$

We can proceed considering the common base of exponentials

$\sqrt[3]{2} \cdot \sqrt[6]{2} = 2^{\frac{1}{3}} \cdot 2^{\frac{1}{6} } = 2^{\frac{3}{6} } = 2^{\frac{1}{2} }=\sqrt{2}$

Therefore,

$5 \sqrt[3]{2} \cdot \sqrt[6]{2} \cdot \sqrt[6]{5} = 5 \cdot \sqrt{2} \cdot \sqrt[6]{5}$

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3 years ago

Find tan A for the triangle below. a 1.5 b. 0.667 C. 0.832 d. 1.202

Kaylis [27]

Answer:

Step-by-step explanation:

on edge

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