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Aleksandr [31]
3 years ago
12

300 milliliters per 'minute = ? liters per hour

Mathematics
1 answer:
Phoenix [80]3 years ago
5 0

Answer:

300 millilters per min = 18 liters per hour

Step-by-step explanation:

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PLEASE HELP ME! find the measure of each numbered angle. pls
zzz [600]

Answer: <em>∠1 = 37.5°; ∠2 = 37.5°; ∠3 = 133°.</em>

Step-by-step explanation:

<em>∠1 = ∠2 = (180° - 105°) ÷ 2 = 37.5°</em>

<em>∠3 = 180° - 23° - 24° = 133°</em>

3 0
3 years ago
What is this math problem<br> -1/12 - (-3/4)
Ivan

Answer:

-1/12 - (-3/4)

= -1/12 + 3/4

= (-1+9)/12

= 8/12

=2/3

3 0
4 years ago
An isosceles trapezoid ABCD with height 2 units has all its vertices on the parabola y=a(x+1)(x−5). What is the value of a, if p
horrorfan [7]

Answer:

a = -0.3575

Step-by-step explanation:

The points A and D lie on the x-axis, this means that they are the x-intercepts of the parabola, and therefore we can find their location.

The points A and B are located where

y=a(x+1)(x-5)=0

This gives

x=-1

y=5

Now given the coordinates of A, we are in position to find the coordinates of the point B. Point B must have y coordinate of y=2 (because the base of the trapezoid is at y=0), and the x coordinate of B, looking at the figure, must be x coordinate of A plus horizontal distance between A and B, i.e

B_x=A_x+\frac{2}{tan(60)} =-1+\frac{2\sqrt{3} }{3}

Thus the coordinates of B are:

B=(-1+\frac{2\sqrt{3} }{3},2)

Now this point B lies on the parabola, and therefore it must satisfy the equation  y=a(x+1)(x-5).

Thus

2=a((-1+\frac{2\sqrt{3} }{3})+1)((-1+\frac{2\sqrt{3} }{3})-5)

Therefore

a=\frac{2}{((-1+\frac{2\sqrt{3} }{3})+1)((-1+\frac{2\sqrt{3} }{3})-5)}

\boxed{a=-0.3575}

8 0
3 years ago
what is the equation subtracting 7 from the product of 4 and a number results in the number added to 29
vitfil [10]

That would be:-

4x - 7 = x + 29

the solution:-

3x = 29 + 7

3x = 36

x = 12


7 0
3 years ago
Find the marginal and average revenue functions associated with the demand function P= -0.3Q + 221
LekaFEV [45]

Answer:

Marginal revenue = R'(Q) = -0.6 Q + 221

Average revenue = -0.3 Q + 221

Step-by-step explanation:

As per the question,

Functions associated with the demand function P= -0.3 Q + 221, where Q is the demand.

Now,

As we know that the,

Marginal revenue is the derivative of the revenue function, R(x), which is equals the number of items sold,

Therefore,

R(Q) = Q × ( -0.3Q + 221) = -0.3 Q² + 221 Q

∴ Marginal revenue = R'(Q) = -0.6 Q + 221

Now,

Average revenue (AR) is defined as the ratio of the total revenue by the number of units sold that is revenue per unit of output sold.

Average\ revenue\ = \frac{Total\ revenue}{number\ of\ units\ sold}

Where Total Revenue (TR) equals quantity of output multiplied by price per unit.

TR = Price (P) × Total output (Q) = (-0.3Q + 221) × Q = -0.3 Q² + 221 Q

Average\ revenue\ = \frac{TR}{Q}

Average\ revenue\ = \frac{-0.3Q^{2}+221Q}{Q}

∴ Average revenue = -0.3Q + 221

5 0
3 years ago
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