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erma4kov [3.2K]
3 years ago
12

I need help I put 30 points for whoever helps me

Mathematics
1 answer:
artcher [175]3 years ago
5 0

Answer:

y=-x+1

Step-by-step explanation:

Slope can be represented as rise over run (change y-values over change in x-values). Since the y-value is changing by -2 every time the x-value is changing by 2, the slope of the line must be \frac{-2}{2}=-1.

In slope-intercept form y=mx+b, m represents the slope of the line, b represents the y-intercept, and (x, y) represent the coordinates of any point the line passes through.

To find b, substitute m=-1 and any point the line passes through.

Using (1, 0) from the table:

0=-1(1)+b,\\0=-1+b,\\b=1

Thus, the equation of this line is \boxed{y=-x+1}

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Help me plz i dont understand how t=40​
timama [110]

Answer:

t=40

Step-by-step explanation:

The sum of all angles in a triangle will always equal 180°. This means that:

(2t-42)+(4t-49)+(2t-49) = 180°

Let's solve this equation!

(2t-42)+(4t-49)+(2t-49) = 180

First we simplify what's on the left side:

2t-42+4t-49+2t-49 = 180

2t+4t+2t-42-49-49 = 180

8t-140 = 180

*Add 140 to both sides

8t = 180+140

8t = 320

Divide both sides by 8 to know what t means:

t = 320/8

t = 40

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3 years ago
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andre [41]

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Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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4 0
3 years ago
What is the slope of the line tangent to the curve y+2 = (x^2/2) - 2siny at the point (2,0)?
kirza4 [7]
<span>, y+2 = (x^2/2) - 2sin(y) so we are taking the derivative y in respect to x so we have dy/dx use chain rule on y so y' = 2x/2 - 2cos(y)*y'

</span><span>Now rearrange it to solve for y' y' = 2x/2 - 2cos(y)*y' 0 = x - 2cos(y)y' - y' - x = 2cos(y)y' - y' -x = y'(2cos(y) - 1) -x/(2cos(y) - 1) = y'
</span><span>we know when f(2) = 0 so thus y = 0 so when f'(2) = -2/(2cos(0)-1)
</span><span>2/2 = 1
</span><span>f'(2) = -2/(2cos(0)-1) cos(0) = 1 thus f'(2) = -2/(2(1)-1) = -2/-1 = 2 f'(2) = 2
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